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Delicious77 [7]
2 years ago
13

Simplify (7^5)^3 A.7^8 B.(1/7)^15 C.35^3 D.7^15

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
8 0

Answer:

\red{{7}^{15} }

Step-by-step explanation:

We know that,

{x}^{a}  \times  {x}^{b}  =  {x}^{a + b}  \\ ( {x}^{a} ) ^{b}  =  {x}^{ab}

Accordingly,

( {7}^{5} ) ^{3}  \\  {7}^{5 \times 3}  \\  {7}^{15}

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Step-by-step explanation:

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Step-by-step explanation:

i) \hspace{0.15cm}\frac{1}{4} batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm} \frac{2}{3} cup \hspace{0.15cm}of\hspace{0.15cm} sugar

ii) multiplying the above by 4 we get

\hspace{0.15cm}(4\times\frac{1}{4}) batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm}( 4 \times\frac{2}{3} )cup \hspace{0.15cm}of\hspace{0.15cm} sugar

iii) Therefore \hspace{0.15cm}1 batch \hspace{0.15cm}of \hspace{0.15cm}cookies\hspace{0.15cm} requires\hspace{0.15cm} \frac{8}{3} cup \hspace{0.15cm}of\hspace{0.15cm} sugar

iv) Therefore a full batch of cookies will require \hspace{0.15cm} \frac{8}{3} cup \hspace{0.15cm}of\hspace{0.15cm} \hspace{0.15cm} sugar,\hspace{0.15cm} or \hspace{0.15cm}2\hspace{0.15cm}whole\hspace{0.15cm} cups\hspace{0.15cm} and \hspace{0.15cm} \frac{2}{3} cup\hspace{0.15cm} of \hspace{0.15cm}sugar.

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