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2 years ago

Simplify (7^5)^3 A.7^8 B.(1/7)^15 C.35^3 D.7^15

Mathematics

1 answer:

oksano4ka [1.4K]2 years ago

8 0

Answer:

$\red{{7}^{15} }$

Step-by-step explanation:

We know that,

${x}^{a} \times {x}^{b} = {x}^{a + b} \\ ( {x}^{a} ) ^{b} = {x}^{ab}$

Accordingly,

$( {7}^{5} ) ^{3} \\ {7}^{5 \times 3} \\ {7}^{15}$

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In 1987, 522 comma 000 people worked in the air transportation industry. In 2003, the number was 480 comma 000. (a) Find a li

umka2103 [35]

Answer:

the linear equation is :

y= -2625x+5737875

and 440000 employees will be in year 2271

Step-by-step explanation:

in order to find the linerar equation let us first convert the given data into (x,y ) co-ordinates i.e

x1= 1987 y1= 522,000

and

x2= 2003, y2 = 480000

according to two point form:

$y-y1 = (y2-y1) \frac{x-x1}{x2-x1}$

In this example we have x1=1987 , y1=522000 , x2=2003 and y2=480000. So,

$y - 522000 = \frac{480000-522000}{2003-1987} (x-1987)\\y- 522000 = -2625(x-1987)\\y- 522000= -2625x+5215875\\\\y= -2625x+5737875$

now to find the year when there will be 440000 employs working , we simply put y= 440000 in the above derived equation

$440000= -2625x+ 5737875\\\\2526x = 5737875 -440000\\2526x = 5736555\\x= \frac{5736555}{2526} \\x= 2271$

7 0

3 years ago

Which of the following products is negative? Select all that apply. *

AlekseyPX

Answer:

(-4)(9)
(6)(-6)

Step-by-step explanation:

$(-4)(-9)\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=4\times\:9\\= 36$

$(-4)(9)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-4\times\:9\\\\\mathrm{Multiply\:the\:numbers:}\:4\times\:9=36\\=-36$

$(6)(6)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=6\times\:6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times\:6\\=36$

$(-6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times\:6\\=36$

$(6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times \:6=36\\=-36$

8 0

3 years ago

A consumer organization estimates that over a 1-year period 20% of cars will need to be repaired once, 8% will need repairs

Sladkaya [172]

Answer:

Probability that a car need to be repaired once = 20% = 0.20

Probability that a car need to be repaired twice = 8% = 0.08

Probability that a car need to be repaired three or more = 2% = 0.02

a) If you own two cars what is the probability that neither will need repair?

Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair= $0.7 \times 0.7=0.49$

b) both will need repair?

Probability both will need repair = $0.3 \times 0.3=0.09$

c)at least one car will need repair

Neither car will need repair= $0.7 \times 0.7=0.49$

Probability that at least one car will need repair= 1-0.49 = 0.51

6 0

3 years ago

What method would you choose to solve the equation 2x2 – 7 = 9? Explain why you chose this method.

Kisachek [45]

This is a quadratic equation . We order to equate to zero

2x² – 7 = 9

2x² - 7-9 = 0
2x² - 16 = 0

This equation is a binomial
2* (x² - 8) = 0
We choose the simplest method . The equation with practice it can be calculated in the memory

The product is equal to 0 if one of the factors is zero

2≠0 ∨ x² - 8 = 0
x² = √8
x = √8 ∨ x= - √8

Answer : x = √8 ∨ x = -√8

5 0

3 years ago

Read 2 more answers

Picking a purple marble from a jar with 15 green and 15 purple marbles.

stepan [7]

Answer:

Then probability is 15/30=1/2

Step-by-step explanation:

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3 years ago