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nordsb [41]
2 years ago
15

Factor the polynomial completely 10³ -25r² - 12r + 30

Mathematics
1 answer:
Olin [163]2 years ago
5 0
ANSWER
(5r^2 - 6)(2r - 5)

EXPLANATION
Factor by grouping
(10r^3 - 25r^2) + (-12r + 30)

Factor a GCF
5r^2 (2r - 5) -6 (2r - 5)

Combine groups
(5r^2 - 6)(2r - 5)

CHECK
Use FOIL

First: 5r^2*2r = 10r^3
Outside: 5r^2*-5 = -25r^2
Inside: -6*2r = -12r
Last: -6*-5 = 30
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A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random.
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corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color  c)the marbles are different in color

Answer:

Step-by-step explanation:

<u><em>The probability was done with replacement.</em></u>

Probaility of an event happening=\frac{number of required outcomes}{number of possible outcomes}

number of blue marbles= 2

number of green marbles=5

total number of marbles=7

(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)

                                  =\frac{2}{7}*\frac{2}{7}

                                   =\frac{4}{49}

(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)

   =\frac{4}{49} + \frac{5}{7}*\frac{5}{7}

   =\frac{4}{49} + \frac{25}{49}

 =\frac{29}{49}

(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)

  =\frac{2}{7}*\frac{5}{7}+ \frac{5}{7}*\frac{2}{7}

           =\frac{10}{49}+\frac{10}{49}

      =\frac{20}{49}

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3 years ago
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