3 years ago

HELP! PLEAAAAAAAAASEE

Mathematics

1 answer:

DerKrebs [107]3 years ago

4 0

What's the question?

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According to the general equation for conditional probability, if P(A upside down u B)= 5/7 and P(B)=7/8 , what is P(A|B)?

natta225 [31]

$P(A | B) = \frac{P(A \cap B)}{P(B)}$

$P(A|B) = \frac{5/7}{7/8}$

$P(A|B) = \frac{5}{7} \div \frac{7}{8}$

$P(A|B) = \frac{5}{7}\times\frac{8}{7}$

$P(A|B) = \frac{5*8}{7*7}$

$P(A|B) = \frac{40}{49}$

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Use photo math for this :)

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Read 2 more answers

The Bobcats had a win-loss record of 41-23 before their star player, Melissa, got injured. Melissa didn’t play in any more games

MrRissso [65]

Answer:

The win percentage decreased by 10%

Step-by-step explanation:

First you need to fin the total games played right before Melissa got Injured

41+23=64

Then you need to find the win percentage by making a fraction of wins over total games

wins/total games = 41/64 = 64%

Then you need to find the number of games played after Melissa got injured

54-41 = 13 wins

34-23 = 11 losses

13+11 = 24 total games played without Melissa

You find that win percentage similarly to the first time

wins/total games = 13/24 = 54%

Then you find the difference in the percentages and there you have it!!

64% - 54% = 10%

It decreased as well therefore the answer is...

It decreased by 10%

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Answer:

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