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2 years ago

If two 6-sided dice are rolled what is the probability that both numbers will be even?

1 answer:

3 0

The probability of one dice rolling an even number is 1/2 as half the numbers are even. Since the events are independent, and there are 2 dice, we need to square 1/2 to get 1/4, assuming they are both fair dice

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Anyone know how to solve this??

Tom [10]

$Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}$

$\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})$

$\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)$

$\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3$

$\implies x^k = x^3$

$\implies k = 3$

7 0

3 years ago

Some help with the circle problem would be much aprecated.

Oksana_A [137]

Try this solution:
for the circle A: circumference=6π, area=9π
for the circle B: circumference=12π, area=36π

PS. formula for circumference is 'L=2πr', for area is 'S=πr²'.

8 0

3 years ago

What is 5x + 12 < 2 ?

Masja [62]

Answer:

x < -2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify.

5x + 12 < 2

Step 2: Solve for x

[Subtraction Property of Equality] Subtract 12 on both sides: 5x < -10
[Division Property of Equality] Divide 5 on both sides: x < -2

5 0

2 years ago

Read 2 more answers

Find the simple interest on $8,000 at 4% interest for 2.5 years?

boyakko [2]

Answer:

800

Step-by-step explanation:

6 0

3 years ago

Find the sample space for the experiment.

Bingel [31]

Answer:

The sample space is:

$AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE$

Step-by-step explanation:

The sample space of an experiment is a set of all the possible values that satisfies that experiment.

The five supervisors are A, B, C, D and E.

Two are to selected.

The number of ways to select 2 supervisors from 5 is: ${5\choose 2}=\frac{5!}{2!(5-2)!} =\frac{5!}{2!\times 3!} = 10$

The sample space will consist of 10 combinations.

The sample space is:

$AB,\ AC,\ AD,\ AE,\\BC,\ BD,\ BE\\CD,\ CE\\DE$

5 0

3 years ago