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nata0808 [166]
2 years ago
13

Which arithmetic sequence has a common difference of -21? ( only one is correct )

Mathematics
1 answer:
Serhud [2]2 years ago
4 0

Answer: c) {1,245; 1,224; 1,203; 1,182; …}

Step-by-step explanation:

<u>Concept:</u>

For this question, we just go by eliminating each answer until we get the correct one

<u>Given information</u>

Common difference = -21 (decreasing sequence)

<u>Answer Choice: a) {873, 894, 915, 936, …}</u>

894 - 873 = <u>21</u>

915 - 895 = <u>21</u>

936 - 915 = <u>21</u>

Since the common difference is 21, not -21

\large\boxed{FALSE}

<u>Answer Choice: b) {32, 20, 8, -4, …}</u>

20 - 32 = <u>-12</u>

8 - 20 = <u>-12</u>

-4 - 8 = <u>-12</u>

Since the common difference is -8, not -21

\large\boxed{FALSE}

<u>Answer Choice: c) {1,245; 1,224; 1,203; 1,182; …}</u>

1224 - 1245 = -<u>21</u>

1203 - 1224 = <u>-21</u>

1182 - 1203 = <u>-21</u>

Since the common difference is -21

\Huge\boxed{TRUE}

<u>Answer Choice: d) {1,563; 1,587; 1,611; 1,635; …}</u>

1587 - 1563 = <u>24</u>

1611 - 1587 = <u>24</u>

1635 - 1611 = <u>24</u>

<u />

Since the common difference is 24, not -21

\large\boxed{FALSE}

Hope this helps!! :)

Please let me know if you have any questions

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9. Combine the radical expression, if possible.
Anastaziya [24]

Answer:

we conclude that:

3\sqrt{125}+4\sqrt{20}=23\sqrt{5}    

Hence, the last option i.e. 23\sqrt{5} is correct.                      

Step-by-step explanation:

Given the expression

3\sqrt{125}+4\sqrt{20}

Combining the radical expressions

3\sqrt{125}+4\sqrt{20}

let us first solve

3\sqrt{125}

=3\sqrt{5^3}

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Apply radical rule:  \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0

=3\sqrt{5^2}\sqrt{5}

Apply radical rule:   \sqrt{a^2}=a,\:\quad \:a\ge 0

=3\cdot \:5\sqrt{5}

=15\sqrt{5}

Thus,

3\sqrt{125}=15\sqrt{5}

similarly solving

4\sqrt{20}

=4\sqrt{2^2\cdot \:5}

Apply radical rule:  \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0

=4\sqrt{2^2}\sqrt{5}

Apply radical rule:   \sqrt{a^2}=a,\:\quad \:a\ge 0

=4\cdot \:2\sqrt{5}

=8\sqrt{5}

Thus,

4\sqrt{20}=8\sqrt{5}

so we get

3\sqrt{125}=15\sqrt{5}

4\sqrt{20}=8\sqrt{5}

so the expression becomes

3\sqrt{125}+4\sqrt{20}=15\sqrt{5}+8\sqrt{5}        ∵ 3\sqrt{125}=15\sqrt{5} , 4\sqrt{20}=8\sqrt{5}

                        =23\sqrt{5}                   ∵ 15\sqrt{5}+8\sqrt{5}=23\sqrt{5}

Therefore, we conclude that:

3\sqrt{125}+4\sqrt{20}=23\sqrt{5}    

Hence, the last option i.e. 23\sqrt{5} is correct.                    

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