The equation of the parabola shown in the 12b is y = x² - 4 if the vertex of the parabola is (0, -4).
<h3>What is a parabola?</h3>
It is defined as the graph of a quadratic function that has something bowl-shaped.
(x - h)² = 4a(y - k)
(h, k) is the vertex of the parabola:
a = √[(c-h)² + (d-k²]
(c, d) is the focus of the parabola:
It is given that:
The graph of a parabola is shown in the 12b question:
As we know, the standard form of the parabola is:
y = a(x - h)² + k
(h, k) is the vertex of the parabola:
From the graph: h = 0, k = -4
y = ax² - 4
Plug (2, 0) in the above equation:
0 = 4a - 4
a = 1
y = x² - 4
Thus, the equation of the parabola shown in the 12b is y = x² - 4 if the vertex of the parabola is (0, -4).
Learn more about the parabola here:
brainly.com/question/8708520
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