Answer:
The incomplete part of the question is "Using a cap-and-trade system of tradable emission allowances will eliminate half of the sulfur dioxide pollution at a cost of $1 million per year. If the permits are not tradable, what will be the cost of eliminating half of the pollution? If permits cannot be traded, then the cost of the pollution reduction will be $1 million per year." The full question is attched as picture as well
1) Tradable permit system
Then lower MAC firm will abate the all pollution units
Then as MAC1 = $250, MAC2 = $275
Firm 1 = Consolidated electric
Firm 2 = Commonwealth utility
Then 1 will sell all permits to 2, at a price between $250 & $275.
So total cost of abatement of 20 units = MAC1 * 20
= $250 * 20 Unit
= $5,000
2) Non-tradable permits
Total cost = MC1*10 + MC2*10
= $2,500 + $2,750
= $5,250
Answer:
<em>Cash markets are also known as</em><em> </em><em><u>spot</u></em><em><u> </u></em><em><u>markets</u></em>
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<em>Spot </em><em>markets</em><em> </em><em>are</em><em>:</em><em> </em><em>markets </em><em>designed </em><em>to</em><em> </em><em>attract</em><em> </em><em>speculator.</em>
It discourages investment from foreign sources
Answer:
$3,340
Explanation:
Step 1 : Determine the Depreciation rate
<em>Depreciation rate = Cost - Salvage Value ÷ Estimated Units</em>
Depreciation rate = $0.10
Step 2 : Depreciation Expense
<em>Depreciation Expense = Depreciation rate x units produced</em>
Depreciation Expense = $3,340
Therefore,
the machine's second-year depreciation using the units-of-production method is $3,340