At michael’s school, 38% of the students have a pet dog and 24% of the students have a pet cat. michael found that 11% of the st
udents had both a pet dog and a pet cat. what is the probability that a randomly chosen student at michael’s school will have a pet dog or a pet cat?
1 answer:
Answer:
0.51 or 51%.
Step-by-step explanation:
If there were 100 students in the school, then 38 have a dog 24 a cat and 11 have both.
So there are 38 - 11 = 27 who only have a dog and 24-11 = 13 who only have a cat.
So total number having a pet = 27+11+13
= 51 students.
So Prob(You will choose a student with a pet) = 51%.
Drawing a Venn diagram would help to answer this and make it clearer.
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So the greatest common factor of 40 and 16 is 8
40/8 : 16/8
5:2
The simplest form of the ratio 40:16 is 5:2
Hope this helps!
Answer:

Step-by-step explanation:

![\textsf{x=1/2[(4x+5)-50]}](https://tex.z-dn.net/?f=%5Ctextsf%7Bx%3D1%2F2%5B%284x%2B5%29-50%5D%7D)







Either c or b. Most likely b
Answer:
8 hours
Step-by-step explanation:
1. Subtract value of tips she got that day
87.05 - 50.25 = 36.8
36.8 is the actual payment for her job that day
2. Divide 36.8 with paid/hour (4.6)
36.8 ÷ 4.6 = 8 hours