Given expression:
To simplify the expression as a fraction in simplest form, let us multiply both terms by 10. Then, both terms must also be divided by 10.
![\implies \dfrac{[10(0.8) - 10(0.6)]}{10}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B%5B10%280.8%29%20-%2010%280.6%29%5D%7D%7B10%7D)
![\implies \dfrac{[8 - 6]}{10}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B%5B8%20-%206%5D%7D%7B10%7D)
![\implies \dfrac{[2]}{10} = \dfrac{2}{10}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B%5B2%5D%7D%7B10%7D%20%3D%20%5Cdfrac%7B2%7D%7B10%7D)
When 2/10 is simplified in lowest terms, we get;

Therefore, 0.8 - 0.6 in fraction form is 1/5.
Answer:
1+√2, 1-√2
Step-by-step explanation:
Since there are 2 factors with an y in the expression, i will assume that there was a mistake in the question and in fact the first term was y³. With that change, we will have that
g(y) = y³-3y²-3y+9
In order to find the critical numbers of g we need to derivate it and equalize the derivate to 0. We can easily derivate g since it is a polynomial:
g'(y) = 3y² - 6y-3
Since g'(y) is a quadratic function, we can obtain the zeros using the quadratic formula, where a = 3, b = -6 and c = -3:

Thus

Therefore, the critical numbers of g are 1+√2 and 1-√2.
I beleive that the problem just ask for that. If you want the critical values, then we need to evaluate those numbers in g. i will do it just in case
g(1 + √2) = (1+√2)³ - 3(1+√2) - 3(1+√2) + 9 = -1.65685
g(1- √2) = (1-√2)³ - 3(1-√2)² -3(1-√2)+9 = 9.6566
34/99=0.34 (34 repeating)
The answer is 9.
5^2=25. 1^5=1. 2^4=16.
Hope it helps :)