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aksik [14]
4 years ago
10

Can someone help and check my work. thank you

Mathematics
1 answer:
docker41 [41]4 years ago
7 0
Everything looks good but the only thing you didn't do in the very last step is to cancel out the 5 in both the numerator and denominator.  Everything is being multiplied together so you're not doing anything "illegal" by canceling the 5's.  In fact, if you're simplifying, you NEED to cancel the 5's.
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Round 547 to the nearest ten and hundred
Anna71 [15]

658...................................


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3 years ago
Express as a trinomial: (2x-3)(x 5)
Illusion [34]
I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.

1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.

(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2x^{2})+(10x)+(-3x)+(-15)=2x^{2}+7x-15

(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2x^{2})+(-10x)+(-3x)+(15)=2x^{2}-13x+15

Your answer is 2x^{2}+7x-15 or 2x^{2}-13x+15. Does that answer your question?
6 0
3 years ago
What is a rational number
Liono4ka [1.6K]

Answer:

The rational numbers (ℚ) are included in the real numbers (ℝ), while themselves including the integers (ℤ), which in turn include the natural numbers (ℕ)

Step-by-step explanation:

5 0
4 years ago
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5 times 10 to the power of 3 times 9 times ten to the power of 7
geniusboy [140]

Answer:

Step-by-step explanation:

450000000000

3 0
3 years ago
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Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

3 0
3 years ago
Read 2 more answers
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