Answer:
the first car has 15 passengers and the second has 10
Step-by-step explanation:
Answer:
<em>Bree spoke at 55 assemblies in this district.</em>
Step-by-step explanation:
Bree speaks at school assemblies charging a school district a total cost C modeled by the equation:
C(a) = 50a+1,500
Being a the number of assemblies attending the meeting.
It's given Bree charged the Escambia City School District $4,250 to speak at school assemblies.
We can find the number of assemblies by solving the equation:
50a+1,500=4,250
Subtracting 1,500:
50a=4,250-1,500=2,750
Dividing by 50;
a = 2,750 / 50=55
Bree spoke at 55 assemblies in this district.
And what I need more information to answer your question.
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Equation 2. If you look at the graph, you see that the slope is negative 3/4 because the rise over run is -3/4. The only equation with the slope -3/4 is 2, so the answer is 2.
