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2 years ago

8

Which function is the inverse of f(x) = -5x- 4?

1 answer:

almond37 [142]2 years ago

3 0

Answer:

Inverse of $- 5 x - 4 =$ $\frac{x + 4}{5}$

Step-by-step explanation:

Let y = -5x-4

Swap y and x

x = -5y -4

Solve for y

x+4 = -5y

$y=- \frac{x + 4}{5}$ which is the inverse

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12) A bag contains four red marbles and eight

DiKsa [7]

Answer: 8/12% 6/11%

Step-by-step explanation: so 4 red marbles and 8 blue marbles so in total that's 12 marbles so if you have 8 blue marbles you have a 3/4 chance of getting blue but only 1/4 chance of red

So 5 green marbles and 6 yellow marbles so in total that's 11 marbles so if you have 6 yellow marbles you have a 3/4 chance of getting yellow but only 1/4 chance of green

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3 years ago

What is the area of the following figure?

disa [49]

Answer:

456 sq ft I think

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3 years ago

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Solving systems of equations using substitution. y=2x+8. y=5-x

kherson [118]

Answer:

(x, y) = (-1, 6)

Step-by-step explanation:

y = 2x + 8

y = 5 - x

Substituting the second equation into the first equation, we get:

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5 = 3x + 8

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So, y = 5 - (-1).

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4 0

2 years ago

Free points, solve 4b+5b=8b-1+3b+15?

vazorg [7]

Answer: Hi!

First, we should combine like terms:

4b + 5b = 8b − 1 +3b + 15 =

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Now, we should subtract 11b from both sides.

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Now, we should divide both sides by -2.

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Hope this helps!

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3 years ago

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Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

$y(1+x)+x-5\ln xy=C$

7 0

3 years ago