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defon
2 years ago
7

Use the given Maclaurin series to evaluate the limit

Mathematics
1 answer:
nekit [7.7K]2 years ago
7 0

The "given series" should be for \cos(x), not x, so that

\cos(x) = 1 - \dfrac{x^2}2 + \dfrac{x^4}{24} - \dfrac{x^6}{720} + \cdots

In the limit (which should say x\to\infty, not n), we have

\displaystyle \lim_{x\to\infty} \frac{\frac{x^2}{1+\cos(x)}}{x^4} = \lim_{x\to\infty} \frac{1}{x^2\left(2 - \frac{x^2}2 + \frac{x^4}{24} - \cdots\right)} = \boxed{0}

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Answer:

The answer is below

Step-by-step explanation:

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