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defon
2 years ago
7

Use the given Maclaurin series to evaluate the limit

Mathematics
1 answer:
nekit [7.7K]2 years ago
7 0

The "given series" should be for \cos(x), not x, so that

\cos(x) = 1 - \dfrac{x^2}2 + \dfrac{x^4}{24} - \dfrac{x^6}{720} + \cdots

In the limit (which should say x\to\infty, not n), we have

\displaystyle \lim_{x\to\infty} \frac{\frac{x^2}{1+\cos(x)}}{x^4} = \lim_{x\to\infty} \frac{1}{x^2\left(2 - \frac{x^2}2 + \frac{x^4}{24} - \cdots\right)} = \boxed{0}

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3 years ago
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3 years ago
Read 2 more answers
I NEED ASAP DUE IN 20 MINS
11111nata11111 [884]

Answer:

y = 45 / 2x + 50

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The best equation for the line of the best fit would be y = 45 / 2x + 50.

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I used the points, ( 0 , 50 ) and ( 4 , 140 ) to get the equation, slope, and the y-intercept.

I used those points because they were the most accurate ones that I know for now.

Also, remember the formula is, "y = mx + b."

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