When you want to find zeros of rational expression you need to find at which points numerator is equal to zero. In this case, we have the product of three expressions.
A product is equal to zero whenever one of the factors is equal to zero.
That means that zeros of our functions are:
1)
2)
3)
The final answer is a. Function has zeros at (0, 1, -11).
Answer:
Step-by-step explanation:
Integer factors of 117 include ...
... 117 = 1×117 = 3×39 ≈ 9×13
The last factor pair is two factors that differ by 4. We can take these to be the dimensions of the rectangle.
_____
If you want to write an equation for width (w), it might be ...
... w(w+4) = 117
... w² +4w -117 = 0
The factorization problem for this quadratic is the problem of finding two factors of 117 that differ by 4. That is what we have done, above.
If you want to solve this by completing the square, you can to this:
... w² +4w = 117
... w² +4w +4 = 121 . . . . . add 4 = (4/2)² to complete the square
... (w+2)² = 121
... w + 2 = ±√121 = ±11 . . . . take the square root
... w = -2 ± 11 . . . . . we're only interested in the positive solution
... w = 9, then w+4 = 13 and the dimensions are 9 cm by 13 cm.
Angles are usually in degrees what do you by correct label for angles?
Answer:
-71 + 22n is the equivalent expression.
This is the simplified expression.
Step-by-step explanation:
4(-11 + 4n) -3(-2n + 9)
= -44 + 16n + 6n - 27
= -44 + 22n - 27
= -71 + 22n
