If these two shapes are similar, what is the measure of the missing length w 20 in 15 in 12 in

I'm super confused on parts g and h because no formula is given, just the limit values. These are the values:

Mrrafil [7]

Answer:

See below.

Step-by-step explanation:

1)

So we have the limit:

$\lim_{x\to 4} (f\circ g)(x)$

This is equivalent to:

$\lim_{x\to 4} f(g(x))$

To solve, we can use the following property:

$\lim_{x \to c} f(g(x))=f( \lim_{x \to c} g(x))$

Therefore, our limit is the same as:

$\lim_{x\to 4} f(g(x))\\=f(\lim_{x\to 4} g(x))$

We are already given that the limit as x approaches 4 of g(x) is -2. Therefore:

$=f(-2)$

You simply need to evaluate this to solve the limit. I don't have enough information to solve this, so maybe you have something more.

Similarly, for the second one:

2)

We have:

$\lim_{x\to 4} (g\circ f)(x)\\=\lim_{x\to 4}g(f(x))$

Using the same property:

$=g(\lim_{x\to 4} f(x))$

And we are told that this is 16, so:

$=g(16)$

And we just need to evaluate this to find the limit.

I hope you find this helpful!

8 0

3 years ago

Eloise is investing in a retirement account. She plans on adding an additional $50 at the end of every year and the expected mon

Lisa [10]

The accumulated (future) value is given by the formula
F=P(1+i)^n
where
P=amount of deposit (made at the beginning of the first period)
i=monthly interest, APR/12 = 3%/12 =0.0025
n=number of periods (month)

For example, the future value for the 6th month is
F(6)=1000(1.0025^6)=1015.09 (to the nearest cent)

Here is a schedule of the values,
i=month
F(i) = value at the end of month i.

i F(i)
0 1000.0
1 1002.5
2 1005.01
3 1007.52
4 1010.04
5 1012.56
6 1015.09
7 1017.63
8 1020.18
9 1022.73
10 1025.28
11 1027.85
12 1030.42 + $50 deposit = 1050.42
All values are rounded to the nearest cent.

6 0

3 years ago

Read 2 more answers

A triangle is shown.

timama [110]

Reflecting over the x axis means to reflect the image vertically, so the result is the second from the right.

Similarly, reflecting over the y axis means to reflect the image horizontally, so the result is the second.

Finally, reflecting over the y=x line means to reflect the image over the bisector of first and third quadrant, so the result is the fourth

5 0

4 years ago

Read 2 more answers

Which function is graphed below?

hoa [83]

Option B. y = 3 (one-third) Superscript x is the function that is graphed in this question.

<h3>How to solve the problem</h3>

We have exponential functions to be of the form abˣ

This can be written in the form of f(x) = $3\frac{1}{3} ^x$

So it crosses through the point (0, 3).

From the way that the curve passes through the circle, we can see that the it is said to pass through at (0, 3) and approaches y = 0 in quadrant 1

Hence this would put our answer to be y = 3 (one-third) Superscript x