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2 years ago

Which characteristic is necessary to create a table that compares two functions?

Mathematics

1 answer:

Eddi Din [679]2 years ago

8 0

The characteristic that is necessary to create a table that compares two functions is D. Choose the same values for each functions .

<h3>What is the usefulness of table?</h3>

The Mathematical tables can be regarded as the lists of numbers which is used in showing the results of a calculation and these can have varying arguments.

It should be noted that when necessary to creating a table that compares two functions it is important to Choose the same values for each functions .

Learn more about mathematical table at:

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Which undefined term can contain parallel lines?

White raven [17]

Coplanor lines that never intersect

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3 years ago

According to the law of reflection, if the angle of incidence of an incoming ray

Natalija [7]

Answer:

The answer is the option B, which is: 46 degrees.

The explanation for this problem is shown below:

1. According to the Law of reflection, the angle of incidence is equal to the angle of reflection.

2. Therefore, if Ф1 is the angle of incidence and Ф2 is the angle of reflection, you have:

Ф1 = 46 degrees

Ф1 = Ф2

Ф2 = 46 degrees

So, the answer is the option mentioned before.

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3 years ago

Read 2 more answers

If STUV is a square with SW = 2x + 13 and WU = 8x - 41, find VT.<br><br> 20 points

sergejj [24]

Answer: VT equals 62

Step-by-step explanation: In the square with sides STUV, the point W is a midpoint on the diagonal of the square such that the diagonal line SU is divided into two equal halves by the lines SW and WU. Also note that a square has two diagonals whose measurements are equal, that is, line SU equals line VT.

If the point W is the midpoint of SU, then we can conclude that SW equals WU. This means;

2x + 13 = 8x - 41

Collect like terms and you now have,

13 + 41 = 8x - 2x

54 = 6x

Divide both sides of the equation by 6

9 = x

Having calculated the value of x, remember that SW plus WU equals SU. And diagonal SU equals diagonal VT.

Therefore, VT is calculated as follows;

VT = SW + WU

VT = 2x + 13 + 8x - 41

VT = 2(9) + 13 + 8(9) - 41

VT = 18 + 13 + 72 - 41

VT = 62

8 0

3 years ago

Two catalysts may be used in a batch chemical process. Twelve batches were prepared using catalyst 1, resulting in an average yi

aalyn [17]

Answer:

a) $t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222$

$df=12+15-2=25$

$p_v =P(t_{25}>6.222) =8.26x10^{-7}$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

b) $(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309$

$(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691$

Step-by-step explanation:

Notation and hypothesis

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

Part a

The system of hypothesis on this case are:

Null hypothesis: $\mu_2 \leq \mu_1$

Alternative hypothesis: $\mu_2 > \mu_1$

Or equivalently:

Null hypothesis: $\mu_2 - \mu_1 \leq 0$

Alternative hypothesis: $\mu_2 -\mu_1 > 0$

Our notation on this case :

$n_1 =12$ represent the sample size for group 1

$n_2 =15$ represent the sample size for group 2

$\bar X_1 =85$ represent the sample mean for the group 1

$\bar X_2 =91$ represent the sample mean for the group 2

$s_1=3$ represent the sample standard deviation for group 1

$s_2=2$ represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

$\S^2_p =\frac{(12-1)(3)^2 +(15 -1)(2)^2}{12 +15 -2}=6.2$

And the deviation would be just the square root of the variance:

$S_p=2.490$

Calculate the statistic

And now we can calculate the statistic:

$t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222$

Now we can calculate the degrees of freedom given by:

$df=12+15-2=25$

Calculate the p value

And now we can calculate the p value using the altenative hypothesis:

$p_v =P(t_{25}>6.222) =8.26x10^{-7}$

Conclusion

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Part b

For this case the confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}$

For the 99% of confidence we have $\alpha=1-0.99 = 0.01$ and $\alpha/2 =0.005$ and the critical value with 25 degrees of freedom on the t distribution is $t_{\alpha/2}= 2.79$

And replacing we got:

$(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309$

$(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691$

7 0

3 years ago

So if the value of the solid's surface area is equal to the volume. Find the value of x

11Alexandr11 [23.1K]

Answer:The solid surface area is equal to the solid volume. Find the value of x? The measurements of the rectangular prism is 11 inches long and 3 inches wide. Height is not listed.

The height of the solid is 5in and the width is 6in. X is the value of the length

Step-by-step explanation:

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3 years ago