If the points of the vertices are (-3,1_,(4,2),(9,-3),(2,-4) then the perimeter of the figure is 28.28 units.
Given points of the vertices of the figure having four sides be (-3,1),(4,2),(9,-3),(2,-4).
We have to find the perimeter of the figure.
Perimeter is the sum of lengths of all the sides of a figure.
First give some name to the points so that it will be easy to understand the sides like A(-3,1),B(4,2),C(9,-3),D(2,-4).
Perimeter of the figure =AB+BC+CD+DA
AB=
=
= units
BC=
=
=units
CD=
=
= units
DA=
=
= units
Perimeter=
=4
=4*5*
=20
=20*1.411
=28.284
After rounding off we will get 28.28 units.
Hence if the points of the vertices are (-3,1_,(4,2),(9,-3),(2,-4) then the perimeter of the figure is 28.28 units.
Learn more about perimeter at brainly.com/question/397857
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