Answer:
Multiply the number of moles of butane by its molar mass, 58.12g/mol, to produce the mass of butane. Mass of butane = 18.8g.
Explanation:
Part B:
The mass of water produced when 4.86 g of butane(C4H10) react with excess oxygen is calculated as below
calculate the moles of C4H10 used = mass/molar mass
moles = 4.86g/58 g/mol =0.0838 moles
write a balanced equation for reaction
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
by use of mole ratio between C4H10 to H2O which is 2:10 the moles of
H20= 0.0838 x10/2 = 0.419 moles of H2O
mass = moles x molar mass
=0.419 molx 18 g/mol = 7.542 grams of water is formed
The concentration of in the stack gas = 12 ppmv
That means 12 L of is present per
The given temperature is 273 K (0 C) and pressure is 1 atm. At these conditions, 1 mol of gas would occupy,
V = 22.4 L
1 mol occupies 22.4 L
Moles of =
Mass of = =μg
Converting :
=
Calculating the concentration in μg/:
Answer:
Heating causes fluid to expand in volume by reducing its density.
Explanation:
Since water does not have charged particles, water is a non-conductor. When some solutes dissolve in water they allow an electric current to flow through the water and the solution conducts electricity. These solutes are called electrolytes. ... Non-electrolytes like sugar dissolve to form molecules in solution.