A square region with perimeter 60 inches is made with square inch tiles. Bob removes one tile from the square and rearranges the
1 answer:
You might be interested in
Step-by-step explanation:
We can model the annual consumption of iron by the equation
c = 900 million tons x , where
n is the number of years after 1993 and
c is the consumption for that year.
An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.
This equation simplifies to
C = 900 million tons x (1.025^n - 1) / ln(1.025), where
x is a dummy variable and
C is the total consumption of iron n years after 1993.
Let R be the amount of iron remaining at n years after 1993, so
R = 480 billion tons - C
R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)
We need to find the value of n when R is 0, so
0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)
Simplify this equation to obtain
n = 107.4
So the iron will run out in the year 1993 + 107 = 2100
Answer: The complete question is found in the attachment
Step-by-step explanation:
a) To determine the 1-unit growth factor for <em>f</em>
= 2.1/1.75 = 1.2
b) To determine the 1-unit percent change for <em>f</em>
<em>=100 x 1-1.2/1 = 0.2 x 100= 20%</em>
<em>c) to determine the initial value of f</em>
<em>f(x)= abˣ , b =1.2 a=initial value</em>
<em>at (-1,2.1)</em>
<em>2.1= (1.2)⁻¹ x a</em>
<em>a = 2.1/(1.2)⁻¹ </em>
<em>a = 2.1 x 1.2 = 2.52</em>
<em />
<em>d) to determine the function formula for f</em>
<em>f(x)= abˣ = 2.52(1.2)ˣ</em>
