Answer:
r = 55°, s = 25°, t = 30°
Step-by-step explanation:
The sum of the interior angles of a quadrilateral = 360°
Sum the 4 angles in the top quadrilateral and equate to 360
r + 100° + 110° + 95° = 360°
r + 305° = 360° ( subtract 305° from both sides )
r = 55°
The sum of the 3 angles in a triangle = 180°
Subtract the sum of the 2 angles from 180° in the left triangle for s
s = 180° - (100 + 55)° = 180° - 155° = 25°
Similarly for the triangle on the right for t
t = 180° - 95 + 55)° = 180° - 150° = 30°
Hello!
Answer:
The answer is C
Step-by-step explanation:
I wrote it in to my graphing calculator
Hope this helps!
Answer:
Hello,
Step-by-step explanation:
![I=\dfrac{Area}{4} =\int\limits^4_0 {\sqrt{16-x^2} } \, dx \\\\Let\ say\ x=4*sin(t),\ dx=4*cos(t) dt\\\\\displaystyle I=\int\limits^\frac{\pi }{2} _0 {4*\sqrt{1-sin^2(t)} }*4*cos(t) \, dt \\\\=16*\int\limits^\frac{\pi }{2} _0 {cos^2(t)} \, dt \\\\=16*\int\limits^\frac{\pi }{2} _0 {\frac{1-cos(2t)}{2}} \, dt \\\\=8*[t]^\frac{\pi }{2} _0-[\frac{sin(2t)}{2} ]^\frac{\pi }{2} _0\\\\=4\pi -0\\\\=4\pi\\\\\boxed{Area=4*I=16\pi}\\](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7BArea%7D%7B4%7D%20%3D%5Cint%5Climits%5E4_0%20%7B%5Csqrt%7B16-x%5E2%7D%20%7D%20%5C%2C%20dx%20%5C%5C%5C%5CLet%5C%20say%5C%20x%3D4%2Asin%28t%29%2C%5C%20dx%3D4%2Acos%28t%29%20dt%5C%5C%5C%5C%5Cdisplaystyle%20I%3D%5Cint%5Climits%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0%20%7B4%2A%5Csqrt%7B1-sin%5E2%28t%29%7D%20%7D%2A4%2Acos%28t%29%20%5C%2C%20dt%20%5C%5C%5C%5C%3D16%2A%5Cint%5Climits%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0%20%7Bcos%5E2%28t%29%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%3D16%2A%5Cint%5Climits%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0%20%7B%5Cfrac%7B1-cos%282t%29%7D%7B2%7D%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%3D8%2A%5Bt%5D%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0-%5B%5Cfrac%7Bsin%282t%29%7D%7B2%7D%20%5D%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0%5C%5C%5C%5C%3D4%5Cpi%20-0%5C%5C%5C%5C%3D4%5Cpi%5C%5C%5C%5C%5Cboxed%7BArea%3D4%2AI%3D16%5Cpi%7D%5C%5C)
12+15=27 then you multiply by 10 and you get your answer
