If military time is 0145, what time is it on a regular clock
1 answer:
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First, find the asymptotes.
When does f(x) become undefined? When the numerator is 0
0=4x-4
4=4x
x=1
Therefore, x cannot be 1, this is a horizontal asymptote.
We also know that when the degree of x in the numerator is smaller than the degree of x in the denominator, y=0.
Now that we have the horizontal asymptotes, find a third point to draw the graph.
If x=2,
f(2)=-3/4(2)-4
=-3/4
Be sure to include this points in your graph.
Hope I helped :)
When does f(x) become undefined? When the numerator is 0
0=4x-4
4=4x
x=1
Therefore, x cannot be 1, this is a horizontal asymptote.
We also know that when the degree of x in the numerator is smaller than the degree of x in the denominator, y=0.
Now that we have the horizontal asymptotes, find a third point to draw the graph.
If x=2,
f(2)=-3/4(2)-4
=-3/4
Be sure to include this points in your graph.
Hope I helped :)
Answer:
PQ =
Step-by-step explanation:
given MQR = 60, PQR = 75
MQP = 75 -60= 15
WE KNOW THAT MQR +QRM +QMR = 180
MPQ = MQP AS ANGLE OPPOSITE TO EQUAL SIDES ARE EQUAL
THEREFORE QMR = 90 - 60 = 30
therefore PQM = 75 - 60 = 15
PM = PQ because M is the mid point
therefore PR = PM +
PR =
PQ =