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Damm [24]
2 years ago
14

Find the greatest common factor of the following terms. A^9b^8,-a^5b^9

Mathematics
2 answers:
nadezda [96]2 years ago
7 0

Answer:

a⁵b⁸

Step-by-step explanation:

Greatest common factor of two expressions is the greatest expression that is a factor of both expressions.

 a⁵ and b⁸ are the greatest factor in both terms.

yKpoI14uk [10]2 years ago
3 0

Answer:

Step-by-step explanation:

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More because it would be starting from 1 then going up to 2 4/5 so that means that he is planning to add music to his playlist.
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3 years ago
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Gabe Industries sells two​ products, Basic models and Deluxe models. Basic models sell for​ $41 per unit with variable costs of​
Hitman42 [59]

Answer:

b. 63 units

Step-by-step explanation:

The breakeven point occurs when the revenue is equal to the expenses. It means that the profit is 0. So, for the Basic model, the revenue is the sell less the costs: $41 - $15 = $26.For the Deluxe model, the revenue per unit is 0 ($45 - $45).

So, calling x the Basic model units, ad y the Deluxe model units, the total revenue will be: 26x, which must be equal to the expenses = $1,310.40:

26x = 1310.40

x = 50.4 units

y = x/4, because for 1 Deluxe model four Basic models are selled.

y = 50.4/4 = 12.6 units

The total units for breakeven point is 50.4 + 12.6 = 63 units.

8 0
4 years ago
Read the photo and please answer!!
Readme [11.4K]

Answer:

<em> 3 + 3x = 45 ; x = 14 </em>

Step-by-step explanation:

45 = 3x + 3 ⇒ <em>x = 14</em>

5 0
3 years ago
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You work at Dave's Donut Shop. Dave has asked you to determine how much each box of a dozen donuts should cost. There are 12 don
Archy [21]

Answer:

Donuts(b) = 12*b

Step-by-step explanation:

Notice that the question is:

What's an expression to model the number of donuts in b boxes?

We know that we are talking of boxes of a dozen donuts.

We know that in one dozen, we have 12 donuts.

Then if we have b boxes, and in each box we have 12 donuts, we will have a total of b times 12 donuts, the expression is:

Donuts(b) = 12*b

There is a lot of information here that we did not use (like the cost of cardboard and donuts), and that may be there just to distract us, the important thing to do here is:

See what is the thing we want to find (in this case, the number of donuts in b boxes)

Find the relevant information to solve this. (ignore the irrelevant information)

Solve the question.

3 0
3 years ago
How many distinct triangles can be formed for which m∠X = 51°, x = 5, and y = 2? zero one two
Vitek1552 [10]
From the law of sines, we have:

\displaystyle{ \frac{\sin \angle X}{x}= \frac{\sin \angle Y}{y}, 

where x and y are the sides opposite to angles X and Y, respectively.


Substituting the known values, we have:



\displaystyle{ \frac{51^{\circ}}{5}= \frac{\sin \angle Y}{2}, thus

                           \displaystyle{ \sin \angle Y=\frac{\sin 51^{\circ}}{5}\cdot2\approx \frac{0.777}{5}\cdot2=0.31.


Using a calculator, we can find that arcsin(0.31)=18 degrees, approximately.

We know that sine of (180-18)=162 degrees is also 0.31. But 162 and 51 degrees add up to more than 180 degrees.

Thus, there is only one triangle that can be formed under these conditions.


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3 years ago
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