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Evgen [1.6K]
2 years ago
13

Write the formula of each compound, and determine its molecular (formula) mass:

Chemistry
1 answer:
Bess [88]2 years ago
4 0

the molecular mass of the magnesium nitrite trihydrate will be 170.3 g/mol and the formula for the magnesium nitrite trihydrate will be Mg(NO_{2})_{2} 3H_{2} O.

A molecule's molecular formula reveals which atoms and the number of each kind are included within it. No subscript will be used if there is just one atom of a certain kind. A subscript is added to the symbol for an atom if it contains two or more atoms of a certain type of atom.

Calculation of the molecular mass as:

Molar mass of Magnesium(Mg) = 24.3 g/mol

Molar mass of nitrogen(N) = 14 g/mol

Molar mass of hydrogen(H) = 1 g/mol

Molar mass of oxygen (O)= 16 g/mol

So, the molecular mass of the magnesium nitrite trihydrate will be (24.3×1) + (14×2) + (16×7) + (1×6)= 170.3 g/mol

Therefore, the molecular mass of the magnesium nitrite trihydrate will be 170.3 g/mol.

To know more about formula

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Is light made up of atoms and elements?•Explain the relationship between matter, atoms, and elements.. •Distinguish between elem
Mars2501 [29]
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</span><span>Describe molecules, and explain how they are formed
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</span><span>Interpret and write some common chemical formulas
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Secondly, a mixture is a combination of two or more substances which are not united using a chemical procedure. The components that make up a mixture do not exist in fixed proportions, and most of the natural substances that you are familiar with, are mixtures. Examples of mixtures include water, alcohol, oil, and dye.

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4 0
4 years ago
What volume in milliliters of 100 proof vodka (50% v/v ethanol) would be likely to kill a typical 360-g rat?
prohojiy [21]

The given question is incomplete, the complete question is:

The LD50 value for ethyl alcohol given orally to rats is 10.3 g/kg. What volume in milliliters of 100 proof vodka (50% v/v ethanol) would be likely to kill a typical 360-g rat?

Answer:

The correct answer is 9.4 ml.

Explanation:

Based on the given information, in rats the LD50 of ethyl alcohol is 10.3 g/kg.

As 1 Kg is 1000 grams

Now the value of LD50 of ethyl alcohol in rats is 10.3 grams/ 1000 grams

The volume of the lethal dose of vodka for a 360 gram rat would be,  

= 360 g × (10.3 g/1000 g)

= 3708 × 10⁻³ g

= 3.708 g

Now the volume of vodka can be determined by using the formula,  

V = mass/density

The density of ethanol is 0.789 g/ml

The volume would be,  

V = 3.708 g/0.789 g/ml

V = 4.70 ml

As 50 percent of Vodka is ethanol, the volume of vodka needed to kill a rat is,  

= 2 × Volume of ethanol

= 2 × 4.70 g/ml

= 9.4 ml

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3 years ago
Which alkane is the isomer of butane called 2-methylpropane?
inessss [21]

Isomers have same formula but the different arrangement of atoms/ structure.

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<span>The structures are as the image.</span>

<span>
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3 0
4 years ago
Read 2 more answers
Normal saline is 0.920% (w/v) NaCl in water. How many grams of NaCl are needed to prepare 15.0 L of normal saline? Normal saline
Rama09 [41]

Answer:

To prepare a 15L 0.920 % NaCl solution we need 138 grams of NaCL

Explanation:

Step 1: Data given

Normal saline is 0.920% (w/v)

⇒ 0.92 g NaCl / 100 mL H2O

Step 2: Calculate grams of NaCl needed to prepare 15 L

We need 0.92 grams of NaCl for 100 mL

We need 9.2 grams of NaCL for 1L

For 15L we need 9.2 grams * 15 = 138 grams of NaCl

To prepare a 15L 0.920 % NaCl solution we need 138 grams of NaCL

3 0
4 years ago
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