Answer:
about 6230 N
Step-by-step explanation:
The mass is given to 3 significant figures, so we need a value for the acceleration due to gravity that is at least 3 significant figures. The standard value is 9.80665 m/s². Using that, the force is ...
... F = ma = (635 kg)(9.80665 m/s²) = 6227.22275 N
Since the mass is only good to 3 significant figures, the force must be rounded to that precision: 6230 N.
Answer:
A
Step-by-step explanation:
We can see there are 2 parts of this function: one line for x<1 (because there is a circle for x=1, meaning it disincludes it) and one line for x >= 1 (because there is a filled circle for x=1, meaning it includes it). Therefore, we can disregard choice B (because it has x <= 1 and x > 1 instead of x<1 and x>= 1).
Notice that the part that x<1 passes through the origin, meaning the y-intercept is 0. In y= mx + b form of a line, b is the y-intercept, so b = 0 and we are looking for something in the form of y = mx for x < 1. Wee see that only in choice A that this is satisfied. Therefore, the answer is A.
I hope this helps! :)
The circle equation is in the format (x – h)² + (y – k)² = r², with the center being at the point (h, k) and the radius being "r".
QUESTION 11.
Equation x²+y²+10x-14y-7 =0 can be rewritten as: x²+10x+25 + y² -14y + 49 -7 - 25 - 49=0
It can be factories as (x + 5)² + (y – 7)² = 9²
Therefore the radius equals 9 and the center is (-5,7)
QUESTION 12.
From equation (x + 4)² + y² = 121
The radius equals √121 = 11 and the center is (-4,0)
QUESTION 13.
As there are missing information in the question, I can't assist. However, you can use the general circle equation (x – h)² + (y – k)² = r² to solve the question.
Finally equations 14 & 15 aren't linear.
Hope that helps you :)
For this case, we perform the conversions:
First roll:
We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.
1 -----------> 4.2
c -----------> 300
You can pack 71 boxes.
Second roll:
We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.
1 -----------> 4.2
c -----------> 70
You can pack 16 boxes.
Third roll:
1 -----------> 4.2
c -----------> 50
You can pack 11 boxes.
Thus, in total you can pack
Answer:
98 boxes
A virus has a volume of about 4.7 x 10⁻¹⁴ cm³
Therefore 4.1 x 10¹⁶ viruses have a volume of
(4.7 x 10⁻¹⁴)(4.1 x 10¹⁶) = 1927 cm³
Answer: 1927 cm³
