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2 years ago

At what temperature (in k) will the density of this liquid be equal to 1.183 g/cm^3

Mathematics

1 answer:

Kobotan [32]2 years ago

3 0

The temperature (in k) at which the density of this liquid will be equal to 1.183 g/cm³ is; 639.6 K

<h3>How to find the temperature from density?</h3>

We are given the formula for density as;

D = 1.246 g/cm³/(1 + 8.324 * 10⁻⁵ K⁻¹ × T)

Where D is density and T is absolute temperature (In K).

If we want a density of 1.183 g/cm³, then we have;

1.183 = = 1.246 g/cm³/(1 + 8.324 * 10⁻⁵ K⁻¹ × T)

Cross multiply to get;

1.183 + (1.183 * 8.324 * 10⁻⁵ * T) = 1.246

1.183 + 0.985 * 10⁻⁴T= 1.246

0.985 * 10⁻⁴T = 1.246 - 1.183

T = 0.063/( 0.985 * 10⁻⁴)

T = 639.6 K

Read more about Temperature and Density at; brainly.com/question/17231176

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