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lara [203]
2 years ago
15

Consider these graphed number lines. 4 number lines going from negative 5 to positive 5. Graph A: closed circles are at negative

5 and positive 2. Everything to the left of negative 5 and to the right of positive 2 is shaded. Graph B: Points are at negative 5 and positive 2. Everything between the points is shaded. Graph C: Open circles are at negative 5 and positive 2. Everything to the left of negative 2 and to the right of positive 2 is shaded. Graph D: Points are at negative 5 and positive 2. Everything between the points is shaded. Which number line represents the solution for the inequality |2p + 3| Greater-than-or-equal-to 7? graph A graph B graph C graph D
Mathematics
1 answer:
blagie [28]2 years ago
3 0

The graph for the solution set of the absolute value inequality is given by graph A.

<h3>What is the absolute value function?</h3>


The absolute value function is given by:

  • |x| = x, x >= 0.
  • |x| = -x, x < 0.

It measures the distance of a point x to the origin, which is given to x = 0.

In this problem, the inequality is given by:

|2p + 3| ≥ 7

Which means that the distance of 2p + 3 to the origin is of at least 7 units, hence 2p + 3 can be:

  • Equal or less to -7.
  • Equal or greater than 7.

Hence:

2p + 3≤ -7

2p ≤ -10

p ≤ -5

2p + 3 ≥ 7

2p ≥ 4

p ≥ 2

The graph is given at the end of the answer, and represented by graph A.

More can be learned about the absolute value function at brainly.com/question/24734454

#SPJ1

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brianna choclotate chip cookies recipe will make about 3 dozen cholotate chip cookies . The recipe calls for 2 1/4 cups of flour
dybincka [34]
So if she uses 2 1/4 for 3/8 thats 5/8 more which is 62.5% so 2 1/4+62.5 of 2 1/4 so 1 7/20+2 1/4 to get 3 3/5.
4 0
3 years ago
If you have 54 blue marbles and 99 yellow marbles, what is the greatest number of identical marble bags that can be made without
shepuryov [24]
The answer should be D) 18 because both 54 and 99 can divide by 3 and when you divide 54 by 3, you get 18 and that's the most bags you can have while still having both colors. Hope I could help.

5 0
4 years ago
Read 2 more answers
Explain how to evaluate f(g(0)).
alekssr [168]

Answer as a fraction:  17/6

Answer in decimal form: 2.8333  (approximate)

==================================================

Work Shown:

Let's use the two black points to determine the equation of the red f(x) line.

Use the slope formula to get...

m = slope

m = (y2-y1)/(x2-x1)

m = (4-0.5)/(2-(-1))

m = (4-0.5)/(2+1)

m = 3.5/3

m = 35/30

m = (5*7)/(5*6)

m = 7/6

Now use the point slope form

y - y1 = m(x - x1)

y - 0.5 = (7/6)(x - (-1))

y - 0.5 = (7/6)(x + 1)

y - 0.5 = (7/6)x + 7/6

y = (7/6)x + 7/6 + 0.5

y = (7/6)x + 7/6 + 1/2

y = (7/6)x + 7/6 + 3/6

y = (7/6)x + 10/6

y = (7/6)x + 5/3

So,

f(x) = (7/6)x + 5/3

We'll use this later.

---------------------

We ultimately want to compute f(g(0))

Let's find g(0) first.

g(0) = 1 since the point (0,1) is on the g(x) graph

We then go from f(g(0)) to f(1). We replace g(0) with 1 since they are the same value.

We now use the f(x) function we computed earlier

f(x) = (7/6)x + 5/3

f(1) = (7/6)(1) + 5/3

f(1) = 7/6 + 5/3

f(1) = 7/6 + 10/6

f(1) = 17/6

f(1) = 2.8333 (approximate)

This ultimately means,

f(g(0)) = 17/6 as a fraction

f(g(0)) = 2.8333 as a decimal approximation

8 0
3 years ago
The figure below shows a trapezoid, ABCD, having side AB parallel to side DC. The diagonals AC and BD intersect at point O.
Harrizon [31]

<u>Answer</u>

double the length of DO


<u>Explanation</u>

For a trapezium, two of the opposites are parallel. The diagonals act like a transverse to the two the pair of parallel lines.

This makes the two diagonals to have some properties.


In the diagram shown, if 2AO = CO, for the other diagonal 2DO = BO.

∴  the length of BO is  double the length of DO.

7 0
3 years ago
Read 2 more answers
Find the solutions for x when y is equal to 0.<br> y = x2 - 3x -18
denis23 [38]
Y = x² - 3x - 18

When y = 0,

x² - 3x - 18 = 0

<span>(x + 3)(x - 6) = 0
</span>
x = -3 or x = 6
3 0
3 years ago
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