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kotykmax [81]
2 years ago
14

Convert the following repeating Decimals to fractions

Mathematics
1 answer:
arsen [322]2 years ago
4 0

Step-by-step explanation:

1. 0.030303......*100

=3.0303....

3.0303..... - 0.030303.... = 3

\frac{99 \times 0.030303}{99}  =  \frac{3}{99}

0.030303 =  \frac{1}{33}

<h3>This is the explination</h3>

2.

=  \frac{1}{3}

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what is the surface area of cone with a diameter of 10 centimeters and a slant height of 12 centimeters round your answer to the
Oduvanchick [21]

The surface area of the cone is 266.9cm^2

Explanation:

The diameter of the cone is 10 cms

Thus, the radius of the cone is given by

r=\frac{d}{2} =\frac{10}{2} =5

The slant height of the cone is 12 cms

The formula for surface area of the cone is given by

$S A=\pi r^{2}+\pi r l$

Substituting the values, we get,

$S A=(3.14)(5)^{2}+(3.14)(5)(12)$

$S A=(3.14)25+(3.14)(60)$

SA=78.5+188.4

SA=266.9cm^2

Thus, The surface area of the cone is 266.9cm^2

5 0
3 years ago
Need Help With Math. One Question
alina1380 [7]

Answer: 2 < x < 16

The triangle inequality theorem says that if we have a triangle with sides a,b,c then

b-a < c < b+a

with b being longer than 'a'

In this case, a = 7 and b = 9 and c = x

so we have

b-a < c < b+a

9-7 < c < 9+7 .... replace a with 7, replace b with 9

2 < c < 16

2 < x < 16 .... replace c with x

So x can be any number between 2 and 16. The value of x cannot be equal to 2. Also, x cannot be equal to 16 either.

8 0
4 years ago
7731 rounded to the nearest 10
Lana71 [14]
7731 Rounded to the nearest 10th is 7,731.0
7 0
3 years ago
50 POINTS! NEED HELP ASAP!
Kitty [74]

Answer:

(8 ,2)

Step-by-step explanation:

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6 0
4 years ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir
Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

\sigma = \sqrt{484} = 22

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

M = z*\frac{\sigma}{\sqrt{n}}

5 = 1.96*\frac{22}{\sqrt{n}}

5\sqrt{n} = 43.12

\sqrt{n} = \frac{43.12}{5}

\sqrt{n} = 8.624

(\sqrt{n})^{2} = (8.624)^{2}

n = 74.4

We need a sample size of at least 75.

6 0
3 years ago
Read 2 more answers
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