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kenny6666 [7]
2 years ago
9

Find the difference of

Mathematics
1 answer:
Colt1911 [192]2 years ago
4 0

Answer:

{x}^{2}  - x + 1

Step-by-step explanation:

subtract the functions as follows:

s(x) - r(x) = (2x+1) - (-x2 +3x)

expand the 2nd bracket by multiplying it by the negative 1 outside

= 2x + 1 + x2 - 3x

= x2 - x + 1

Voila!

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Read 2 more answers
How do I simplify ((3x^2+12x+12)/(2x^2+x-6))/((4x^2-9)/(3x^3+x^2-10))
Shalnov [3]
\dfrac{ \frac{3x^2+12x+12}{2x^2+x-6} }{ \frac{4x^2-9 }{3x^3+x^2-10} } =

= \dfrac{3(x + 2)^2}{(2x - 3)(x + 2)} \times \dfrac {3x^3+x^2-10} {(2x + 3)(2x - 3)} }

= \dfrac{3(x + 2)}{2x - 3} \times \dfrac {3x^3+x^2-10} {(2x + 3)(2x - 3)} }

= \dfrac{3(x + 2)(3x^3+x^2-10) }{(2x - 3)^2(2x + 3)}




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