Question

A spinner has 8 equally sized sections, 4 of which are gray and 4 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue ? Write your answer as a fraction in simplest form.

Answer 1

I believe it is 1/4. Lala taking up space

Answer 2

Answer:

Probability of first spin which lands on gray and blue in second spin will be 1/4.

Step-by-step explanation:

A spinner has 8 equally sized sections, 4 of which are gray and 4 are blue.

The spinner is spun twice. So the probability that the first spin lands on gray will be = 4/8 = 1/2

Similarly in second spin the probability of landing on blue = 4/8 = 1/2

Since both the events are individual events therefore the probability of happening both the events = (1/2)×(1/2) = 1/4

So the answer is 1/4.