Given m n, find the value of x.
2 answers:
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We are given: Price of stock on 1st January = $10.
And price of stock on 31st january = $12.
Let us represent Day number and Price by coordinate (x,y).
Therefore, coordinates for January month can be written as (1,10) and (31,12).
Price of stock on 1st February = $10.
And price of stock on 28th February = $9.
Let us represent Day number and Price by coordinate (x,y).
Therefore, coordinates for February month can be written as (1,12) and (28,9).
Now, we can plot those two different pairs of coordinates for January and February on the graph.
From the graph, we can see that slope of red line is greater and it is positive and slope of green line is negative(because price decreasing).
Therefore, the price change from $10 to $9 is not a straight line.
Therefore, we can say from January 1 to January 31 the rate is inceasing so the slope is positive then after 1 February the rate started decreasing so the slope became negative.
Answer:
0% probability that, for any day, the number of special orders sent out will be no more than 33
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 66 special orders daily
This means that . We have the mean during a time interval, which means that the number of special orders follow a Poisson distribution, which has
What is the probability that, for any day, the number of special orders sent out will be no more than 33?
Since the Poisson distribution, which is discrete, is approximated to the normal(which is continuous), we have to use continuity correction, and thus, this probability is P(X < 33 - 0.5) = P(X < 32.5), which is the p-value of Z when X = 32.5.
has a p-value of 0.
0% probability that, for any day, the number of special orders sent out will be no more than 33