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yuradex [85]
2 years ago
8

19. 9a2b = c + 4a, for a

Mathematics
1 answer:
xenn [34]2 years ago
5 0

Answer:x/5 + 2b/5

Step-by-step explanation:

9a-2b=c+4a solve for a

9a-2b=c+4a

add -4a to both sides

9a-4a-2b=x+4a-4a

5a-2b=x

add 2b to both sides

5a-2b+2b=x+2b

5a= x+2b

divide by 5

5a/5 = x/5 +2b/5

a= x/5 + 2b/5

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3 years ago
Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
Romashka [77]

Answer:

(a) The mean score of test A is 1210.

(b) The mean score of test A is 1210.

(c) The standard deviation of  test A is 80.

(d) The value of Q₃ for test A is 1170.

(e) The value of median for test A is 1090.

(f) The value of IQR for test A is 290.

Step-by-step explanation:

The relation between two standardized tests <em>A</em> and <em>B</em> is:

50A=40B+50

The equation above approximates the relationship between scores on the two tests.

The summary statistics for test B are as follows:

Lowest Score = 21

Mean score = 29

Standard deviation = 2

Q₃ = 28

Median = 26

IQR = 6

(a)

Compute the lowest score on test A as follows:

A=40B+50\\=(40\times21)+50\\=890

Thus, the lowest score on test A is 890.

(b)

Compute the mean score of test A as follows:

<h2>A=40B+50\\=(40\times29)+50\\=1210</h2>

Thus, the mean score of test A is 1210.

(c)

Compute the mean score standard deviation of test A as follows:

<h2>A=40B+50\\=(40\times2)\\=80</h2>

Thus, the standard deviation of  test A is 80.

(d)

Compute the value of Q₃ for test A as follows:

A=40B+50\\=(40\times28)+50\\=1170

Thus, the value of Q₃ for test A is 1170.

(e)

Compute the value of median for test A as follows:

A=40B+50\\=(40\times26)+50\\=1090

Thus, the value of median for test A is 1090.

(f)

Compute the value of IQR for test A as follows:

A=40B+50\\=(40\times6)+50\\=290

Thus, the value of IQR for test A is 290.

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Nadusha1986 [10]

Answer:

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Step-by-step explanation:

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