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2 years ago

What can reasonably be inferred about gliding

Mathematics

1 answer:

AveGali [126]2 years ago

6 0

Correct option is C. They use the ground for feeding more often than

for perching.

High-flying animals use the ground for food and movement, but very rarely perch. The passage indicates that flying animals flap their wings when climbing steep slopes and runways.

Therefore, option D is incorrect. The statements of option A and B are not supported by text and are therefore incorrect.

"At field sites around the world, Ken Dial saw a pattern in how young pheasants, quail, tinamous, and other ground birds ran along behind their parents. “They jumped up like popcorn,” he said, describing how they would flap their half-formed wings and take short hops into the air. So when a group of graduate students challenged him to come up with new data on the age‑old ground-up-tree-down debate, he designed a project to see what clues might lie in how baby game birds learned to fly.

Ken settled on the Chukar Partridge as a model species, but he might not have made his discovery without a key piece of advice from the local rancher in Montana who was supplying him with birds. When the cowboy stopped by to see how things were going, Ken showed him his nice, tidy laboratory setup and explained how the birds’ first hops and flights would be measured. The rancher was incredulous.

...........................................

W A I R takes on surprising explanatory powers. With one fell swoop, the Dials came up with a viable origin for the flapping flight stroke of birds (something gliding animals don’t do and thus a shortcoming of the tree-down theory) and an aerodynamic function for half-formed wings (one of the main drawbacks to the ground-up hypothesis)."

To learn more about passages from given link

brainly.com/question/25950911

#SPJ4

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A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

Mkey [24]

Answer:

(a) Probability that 2 or fewer will withdraw is 0.2061.

(b) Probability that exactly 4 will withdraw is 0.2182.

(c) Probability that more than 3 will withdraw is 0.5886.

(d) The expected number of withdrawals is 4.

Step-by-step explanation:

We are given that a university found that 20% of its students withdraw without completing the introductory statistics course.

Assume that 20 students registered for the course.

The above situation can be represented through binomial distribution;

$P(X =r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,......$

where, n = number of trials (samples) taken = 20 students

r = number of success

p = probability of success which in our question is probability

that students withdraw without completing the introductory

statistics course, i.e; p = 20%

Let X = Number of students withdraw without completing the introductory statistics course

So, X ~ Binom(n = 20 , p = 0.20)

(a) Probability that 2 or fewer will withdraw is given by = P(X $\leq$ 2)

P(X $\leq$ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= $\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}$

= $1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}$

= 0.2061

(b) Probability that exactly 4 will withdraw is given by = P(X = 4)

P(X = 4) = $\binom{20}{4} \times 0.20^{4} \times (1-0.20)^{20-4}$

= $4845\times 0.20^{4} \times 0.80^{16}$

= 0.2182

(c) Probability that more than 3 will withdraw is given by = P(X > 3)

P(X > 3) = 1 - P(X $\leq$ 3) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1-(\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}+\binom{20}{3} \times 0.20^{3} \times (1-0.20)^{20-3})$

= $1-(1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}+1140\times 0.20^{3} \times 0.80^{17})$

= 1 - 0.4114 = 0.5886

(d) The expected number of withdrawals is given by;

E(X) = $n\times p$

= $20 \times 0.20$ = 4 withdrawals

3 0

4 years ago

Pls help I’m really confused I’ll give you 35 pints

rjkz [21]

Answer:

The total payment is thus $35.75 plus $7.11, or $42.86

Step-by-step explanation:

Note that the sales tax doesn't affect the tip. The sales tax is 5% of the cost and the tip is 15% of the before tax cost. We calculate the tax and the tip separately, then add them together and finally add this sum to the cost.

Sales tax: 5% of $35.75: $1.75

Tip: 15% of $35.75: $5.36

Adding these two quantities results in $7.11.

The total payment is thus $35.75 plus $7.11, or $42.86

8 0

3 years ago

How do you write 7,100 in scientific notation

IRISSAK [1]

Answer:

7.1 x 10³

Step-by-step explanation:

Move your decimal so that it follows your first whole number greater than zero. The number of places you moved the decimal is the same as the exponent. Since the number 7.1 needs to INCREASE to be 7,100, then the exponent is positive.

3 0

3 years ago

Read 2 more answers

A labtop has ablisted price of $739.98 befire tax. If the sales tax rate is 8.75%, find the total cost of the labtop with sales

podryga [215]

The total was 804.73 pretty sure

8 0

3 years ago

Which 2.85 tons rounded to the nearest hundredth

kotykmax [81]

Answer: 3.00 tons.

Step-by-step explanation:

Nearest hundred: 2.85 = 3.00

Nearest tenth: 2.85 = 2.90

I know you already have the answer but I hope this helps you!

3 0

3 years ago