This is an expression equivalent to the problem (f g) (10)
Answer:
B. y =
+ 6
Step-by-step explanation:
Answer:
-√32 < 59/11 < √30 < 5.49
Answer:
![\angle 1 = 99^\circ](https://tex.z-dn.net/?f=%5Cangle%201%20%3D%2099%5E%5Ccirc)
![\angle 3 = 99^\circ](https://tex.z-dn.net/?f=%5Cangle%203%20%3D%2099%5E%5Ccirc)
![\angle 4 = 81^\circ](https://tex.z-dn.net/?f=%5Cangle%204%20%3D%2081%5E%5Ccirc)
Step-by-step explanation:
Given
![\angle 2 = 81^\circ](https://tex.z-dn.net/?f=%5Cangle%202%20%3D%2081%5E%5Ccirc)
Required
Determine: ![\angle 1 . \angle 3 , \angle 4](https://tex.z-dn.net/?f=%5Cangle%201%20.%20%5Cangle%203%20%2C%20%5Cangle%204)
Solving for
, we have:
--- angle on a straight line
So, we have:
![\angle 1 = 180^\circ-\angle 2](https://tex.z-dn.net/?f=%5Cangle%201%20%3D%20180%5E%5Ccirc-%5Cangle%202)
![\angle 1 = 180^\circ-81^\circ](https://tex.z-dn.net/?f=%5Cangle%201%20%3D%20180%5E%5Ccirc-81%5E%5Ccirc)
![\angle 1 = 99^\circ](https://tex.z-dn.net/?f=%5Cangle%201%20%3D%2099%5E%5Ccirc)
To solve for
, we have:
![\angle 3 = \angle 1](https://tex.z-dn.net/?f=%5Cangle%203%20%3D%20%5Cangle%201)
--- Vertically opposite angles
So:
![\angle 4 = 81^\circ](https://tex.z-dn.net/?f=%5Cangle%204%20%3D%2081%5E%5Ccirc)
![\angle 3 = 99^\circ](https://tex.z-dn.net/?f=%5Cangle%203%20%3D%2099%5E%5Ccirc)
A proportional dimension will change the perimeter by the factor of itself. And will change the area by the factor of the dilation squared.