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2 years ago

The cost of safely disposing/A of the toxic chemicals is approximately/B

1 answer:

3 0

The cost of safely disposing of the toxic chemicals is approximately five times what the company paid to purchase it.(Option D)

<h3>What is sentence correction?</h3>

Sentence correction or sentence improvement is a type of grammatical practice where a sentence is given with a word or a phrase that requires grammatical changes or improvement.

Now,

Here, we are talking about "toxic chemicals", that is "plural" but in the Part D of the sentence, "it" refers to the singular chemical.

Hence, the correction needs to be made at Option D; the correction would be: "paid to purchase them."

To learn more about sentence correction, refer to the link: brainly.com/question/14632568

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What two products do you get when you cross-multiply the fractions 2/5 and 3/8?

jarptica [38.1K]

Answer: a. 10 and 12

explanation:

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3 years ago

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3 years ago

Any one that knows this please help thanks : )

Olin [163]

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3 years ago

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An equation for the depreciation of a car is given by y = A(1 – r)t , where y = current value of the car, A = original cost, r =

Mamont248 [21]

<h2>The car is about 6.6 years old.</h2>

Step-by-step explanation:

Given : An equation for the depreciation of a car is given by $y = A(1-r)^t$ , where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years. The value of a car is half what it originally cost. The rate of depreciation is 10%.

To find : Approximately how old is the car?

Solution :

The value of a car is half what it originally cost i.e. $y=\frac{1}{2} A$

The rate of depreciation is 10% i.e. r=10%=0.1

Substitute in the equation, $y = A(1-r)^t$

$\frac{1}{2} A= A(1-0.1)^t$

$\frac{1}{2}= (0.9)^t$

Taking log both side,

$\log(\frac{1}{2})=t\log (0.9)$

$t=\frac{\log(\frac{1}{2})}{\log (0.9)}$

$t=6.57$

$t\approx 6.6$

Therefore, the car is about 6.6 years old.

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3 years ago

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What is the length of LINE GH?<br> And please explain why thank you:

lesya692 [45]

co-ordinates of point G are (1,2)

co-ordinates of point H are (3,-3)

so, by distance formula :

$\sqrt{( {x1 - x1})^{2} + ( {y1 - y2})^{2} } \\ = \sqrt{( {1- 3})^{2} + ( {2 - ( - 3)})^{2} } \\ \sqrt{( { - 2})^{2} + ( {2 + 3})^{2} } \\ \sqrt{( { - 2})^{2} + ( {5})^{2} } \\ \sqrt{4 + 25} \\ \sqrt{29}$

so, it is root(29) or 5.38 units

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3 years ago