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Paladinen [302]
2 years ago
15

Write an equation that has of constant of proportionality of 15.

Mathematics
1 answer:
hoa [83]2 years ago
4 0
Hello there! The formula for constant of proportionality is k = y/x, which also is k = slope.

Equations with a constant of proportionality of 15 would be:

• k = 15/1

• k = 30/2

•k = 75/5

and so on. Anything that is a multiple of 15 and is placed as the numerator over the dividend used to receive a quotient of 15 would work. Hope this helps!
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An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
What is greater than 1 cup
77julia77 [94]
2 cups your welcome
5 0
3 years ago
Answer the following
serg [7]

Answer:

Step-by-step explanation:

61)4 + 5(p-1) = 34     {Distributive property}

    4 + 5p - 5 = 34   {Add like terms}

         5p - 1   = 34     {Add 1 to  both sides}

             5p  = 34+1

              5p = 35  {Divide both sides by 5)

                p  = 35/5

               p = 5

62)    Smaller angle = x

Larger angle = x +50

x + (x +50) = 180       {Supplementary angles}

 2x + 50   = 180  {Subtract 50 from both sides}

          2x  = 180 -50

            2x = 130

              x = 130/2

            x = 65

Smaller angle = 65

Larger angle = 65 + 50 = 115

63) ΔBAD , ΔBCD

BA ≅ BC

∠A ≅ ∠C

AD ≅ CD

ΔBAD ≅ΔBCD        {S A S congruent}

64) Selling price = ₹ 5500

Profit = 10%

Cost price = \frac{100}{100+profit}*SP\\\\= \frac{100}{100+10}*5500\\\\=\frac{100}{110}*5500\\\\=100*50\\\\=5000=

6 0
2 years ago
Which expression is equivalent to square root 25x^9
tekilochka [14]
√((25x^9y^3)/(64x^6y^11))  doing the normal division within the radical

√((25x^3)/(64y^8)  then looking at the squares within the radical...

√((5^2*x^2*x)/(8^2*y^8))  now we can move out the perfect squares...

(5x/(8y^4))√x

So it is the bottom answer...
3 0
3 years ago
Can someone please help with with this question
stiks02 [169]

Answer:

Try asking your teacher for some help, so he/she can explain it more to you if you don't understand

Step-by-step explanation:

6 0
2 years ago
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