Take the derivative with respect to t

the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero

divide by w

we add sin(wt) to both sides

divide both sides by cos(wt)

OR

(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

since 2npi is just the period of cos

substituting our second soultion we get

since 2npi is the period

so the maximum value =

minimum value =
Answer:
Step-by-step explanation:
61)4 + 5(p-1) = 34 {Distributive property}
4 + 5p - 5 = 34 {Add like terms}
5p - 1 = 34 {Add 1 to both sides}
5p = 34+1
5p = 35 {Divide both sides by 5)
p = 35/5
p = 5
62) Smaller angle = x
Larger angle = x +50
x + (x +50) = 180 {Supplementary angles}
2x + 50 = 180 {Subtract 50 from both sides}
2x = 180 -50
2x = 130
x = 130/2
x = 65
Smaller angle = 65
Larger angle = 65 + 50 = 115
63) ΔBAD , ΔBCD
BA ≅ BC
∠A ≅ ∠C
AD ≅ CD
ΔBAD ≅ΔBCD {S A S congruent}
64) Selling price = ₹ 5500
Profit = 10%

√((25x^9y^3)/(64x^6y^11)) doing the normal division within the radical
√((25x^3)/(64y^8) then looking at the squares within the radical...
√((5^2*x^2*x)/(8^2*y^8)) now we can move out the perfect squares...
(5x/(8y^4))√x
So it is the bottom answer...
Answer:
Try asking your teacher for some help, so he/she can explain it more to you if you don't understand
Step-by-step explanation: