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Degger [83]
1 year ago
15

Please solve. NO EXPLAINATION NEEDED. I NEED ANSWER FAST

Mathematics
1 answer:
nexus9112 [7]1 year ago
4 0

Answer:

11 and 22

Step-by-step explanation:

We can say that BC=2AC.

Since AB=33, AC=11 and BC=22.

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Find the solution to the equations. 2x - y = -3 x y = 0 (0, 0) (-1, 1) (1, -1)
rosijanka [135]
(2x-y = -3 × y = 0 × (0, 0) × ( -1, 1) × (1, -1) = (2x - y = -3 × y =0 × (0)) ×, × 0 ×, × 1 ×, × -1
4 0
3 years ago
Find the value of x.
azamat

Answer:

98 °

Step-by-step explanation:

We know that the sum of the angles in a triangle is 180. We also know that angle DAB is 122°, meaning that angle CAB is 180-122, which is 58°. We also know that angle CBA is 24 degrees. Therefore, angle x is just 180-(58+24), which is 98

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2 years ago
Which point is on the graph of the function y=3x+2<br>A.(1,5)<br>B.(2,3)<br>C.(3,2)<br>D.(5,1)​
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Answer:

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Step-by-step explanation:

4 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

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2 years ago
What is the sales tax of a $249 cell phone if the tax rate is 8%​
raketka [301]
$19.92 is the answer
7 0
3 years ago
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