Ask question

Ask question

All categories

Anestetic [448]

3 years ago

9

The function f(t) = 16 represents the distance (in feet) a dropped object falls in t seconds. The function g(t) = s, represents

the
initial height (in feet) of the object. A necklace is dropped from a height of 36 feet. After how many seconds does the necklace hit the
ground?

1 answer:

Lady bird [3.3K]3 years ago

3 0

Answer:

16

Step-by-step explanation:

You might be interested in

Which expressions is equivalent to 2r+(t+r)

azamat

Answer:

t+3r

Step-by-step explanation:

This is a one step solution

All you do is add like terms

In this case the only like terms are the varibles r

2r+(t+r)

so if you add all of the rs together there would be 3rs

So the rest of the problem would continue as normal while bringing the 3r to the end

t+3r

8 0

3 years ago

Please help me simplify 4^8/4^5

Oksi-84 [34.3K]

Answer:

64

Step-by-step explanation:

64

Hope it helped!

4 0

3 years ago

Read 2 more answers

What’s the slope and y - intercept of this equation ?

zavuch27 [327]

Answer:

Slope = - $\frac{7}{3}$

Y-intercept = 4

Step-by-step explanation:

-> See attached

-> This equation is in slope-intercept form.

[] When we use y = mx + b, the m is the slope and the b is our y-intercept.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

5 0

3 years ago

Read 2 more answers

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

4 years ago

Answer fast please. I'll mark brainliest.

Kryger [21]

Answer:

the answer is d; the slope is 4, and the y-intercept is 12

Step-by-step explanation:

the slope is actually 4/-1, but the y-intercept is still 12 thow.

5 0

3 years ago