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galben [10]
2 years ago
11

Please help with these 2 problems

Mathematics
1 answer:
HACTEHA [7]2 years ago
4 0

(\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} } = \frac{16}{9}

4ˣ⁻¹ = 49 / 4

<h3>How to simplify an expression?</h3>

The expressions can be simplified as follows;

(\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} }

Hence,

(\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} } = (\frac{4}{3} )^{2(\frac{2}{3} )}.(\frac{4}{3} ) ^{\frac{5}{3} }

Therefore,

(\frac{4}{3} )^{2(\frac{2}{3} )}.(\frac{4}{3} ) ^{\frac{5}{3} } = (\frac{4}{3} )^{\frac{4}{3} } .(\frac{4}{3} )^{\frac{5}{3} }

Finally,

(\frac{4}{3} )^{\frac{4}{3} } .(\frac{4}{3} )^{\frac{5}{3} } = (\frac{4}{3} )^{3}

(\frac{4}{3} )^{3} = \frac{16}{9}

2ˣ = 7

4ˣ⁻¹ = 2²⁽ˣ⁻¹⁾ = 2²ˣ ⁻ ²  = 2²ˣ / 2² = (2ˣ)² / 2²

Therefore,

(2ˣ)² / 2² = 7² / 2² = 49 / 4

Hence,

4ˣ⁻¹ = 49 / 4

Finally, the  (\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} } is equal to \frac{16}{9}  and for the second part  4ˣ⁻¹ = 49 / 4

learn more on simplification here: brainly.com/question/17513857

#SPJ1

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Option D is correct.

Step-by-step explanation:

The vertices of given parallelogram ABCD are A(2,1),B(3,4),C(5,3), and D(4,0).

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Keywords: Reflection across x-axis

Learn more about reflection across x-axis at:

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