Y=radical 3
just cancel out the 2 on both sides
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
If a = 10, then the equation would be 10+6.
The answer would be 16.
Hope this helps! :D
true...
cus their angles are same... if you rotate the second triangle once to the left side
hope it helps...!!!
Answer:
m<ABC = 45
m<DBC = 34°
Step-by-step explanation:
Given:
m<ABD = 79°
m<ABC = (8x - 3)°
m<DBC = (5x + 4)°
Step 1: Generate an equation to find the value of x
m<ABC + m<DBC = m<ABD (angle addition postulate)
(8x - 3) + (5x + 4) = 79
Solve for x
8x - 3 + 5x + 4 = 79
13x + 1 = 79
Subtract 1 from both sides
13x + 1 - 1 = 79 - 1
13x = 78
Divide both sides by 13
x = 6
Step 2: find m<ABC and m<DBC by plugging the value of x into the expression of each angle
m<ABC = (8x - 3)°
m<ABC = 8(6) - 3 = 48 - 3 = 45°
m<DBC = (5x + 4)°
m<DBC = 5(6) + 4 = 30 + 4 = 34°
Step-by-step explanation:
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