Answer:
A=60, B=80, and C=67
Step by step explanation:
B= 2a
C= a+27
With the information, you get the equation:
A+A+27+2A=187
Then, you have to simplify.
You then get 4a+27=187.
Now, you subtract 27 from both sides to get: 4a=60.
Divide both sides by 4 to get A= 60.
If A=60, 2A=80, so B=80. A+27=67, so C=67.
You check this by adding them up to see if they equal to 187, which in fact, they do.
A=60, B=80, and C=67.
Hope this helped!
Measure it hope that helps if not that's on me
Answer:
The answer to the equation should be -2
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be parallel, they have to have the same slope.
y = 6x + 6 The slope of this line is 6, so the parallel line's slope is also 6.
Now that you know m = 6, substitute/plug it into the equation:
y = mx + b Plug in 6 for "m" in the equation
y = 6x + b To find "b", plug in the point (20, 1) into the equation
1 = 6(20) + b
1 = 120 + b Subtract 120 on both sides to get "b" by itself
1 - 120 = 120 - 120 + b
-119 = b Now that you know b = -119, plug it into the equation
y = 6x - 119
compare the triangles ΔABC and ΔBCD
∡ABC = ∡BCD (given)
AB = CD (given)
BC = BC (common) } = > (SAS) ΔABC ≡ ΔBCD = > AC = BD
