Q1=3 Q2[median]=12 Q3=14 and the IQR is 11
Answer:
8
Step-by-step explanation:
Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)
Answer:
no solutions
Step-by-step explanation:
10x+2y=42
5x+y=20
Multiply the second equation by -2 to use elimination
-2(5x+y)=20*-2
-10x -2y = -40
Add this to the first equation
10x+2y=42
-10x -2y = -40
--------------------------
0 = 2
This is never true. This means there are no solutions