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2 years ago

Determine whether the equation below has a one solutions, no solutions, or an

1 answer:

4 0

The equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions

<h3>How to determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions?</h3>

The equation is given as:

x + 2 = 2 + x

Collect the like terms

x - x =2 - 2

Evaluate the like terms

0 = 0

An equation that has a solution of 0 = 0 has an infinite number of solutions

Possible values of x are x = 8 and x = -8

Hence, the equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions

Read more about number of solutions at

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Someones answer q3 ill mark as brainliest pleaseee

il63 [147K]

The length of the rectangle is x and the height is x-2

To find the area of a rectangle you multiply length times width

l(w) = 146

x(x-2) = 146

x^2 - 2x = 146

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3 years ago

En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que

Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

$h_1$ = Altura del frasco corto

$h_2$ = La altura del frasco alto es el doble que el del frasco corto. = $2h_1$

$d_1$ = Diámetro del frasco corto

$d_2$ = El diámetro del frasco alto es la mitad del frasco corto = $\dfrac{1}{2}d_1$

El volumen de un cilindro es $\pi \dfrac{d^2}{4}h$

La razón de los volúmenes de los frascos es

$\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2$

El costo del frasco corto por unidad de volumen es

$\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}$

El costo del frasco alto por unidad de volumen es

$\dfrac{4500}{V_2}=\dfrac{4500}{V_2}$

$\dfrac{4000}{V_2}$

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

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3 years ago

ANSWER FOR BRAINLIEST:

AlekseyPX

Step-by-step explanation:

I think mode,range and median dpo ako sure

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3 years ago

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3 years ago

Y-1/4=-3/8 solve for y

Leona [35]

Answer:

y=-1/8

Step-by-step explanation:

Add 1/4 to -3/8

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3 years ago