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2 years ago

Determine whether the equation below has a one solutions, no solutions, or an

1 answer:

4 0

The equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions

<h3>How to determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions?</h3>

The equation is given as:

x + 2 = 2 + x

Collect the like terms

x - x =2 - 2

Evaluate the like terms

0 = 0

An equation that has a solution of 0 = 0 has an infinite number of solutions

Possible values of x are x = 8 and x = -8

Hence, the equation below does not have one solution, or no solutions, but instead it has an infinite number of solutions

Read more about number of solutions at

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Use the quadratic formula to solve the equation.–x2 + 5x = 3

Karo-lina-s [1.5K]

Given the equation - x² + 5x = 3, which can be rewritten as:

- x² + 5x - 3 = 0

where a = -1, b = 5 and c = -3.

Quadratic formula:

$\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2\text{ - 4ac}}}{2a}$

Now, we just replace the values of a, b and c on the equation above.

$\frac{-5\text{ }\pm\text{ }\sqrt[]{5^2\text{ - 4(-1)(3)}}}{2(-1)}$

$\frac{5}{2}\text{ }\pm\text{ }\frac{\sqrt[]{13}}{2}$

4 0

1 year ago

10. Use the properties of exponents to simplify the expression:

aivan3 [116]

<h3><u>Answer</u> :</h3>

$\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}$

Let's solve !

$:\implies\sf\:25^{\frac{3}{2}}$

$:\implies\sf\:(\sqrt[2]{25})^3$

$:\implies\sf\:5^3$

$:\implies\boxed{\bf{\red{125}}}$

<u>Hence, Oprion-D is correct</u> !

7 0

3 years ago

Mark wants to be a millionaire by the time he retires at age 65. He assumes there is a 6% annual interest rate. If he starts sav

Mashutka [201]

Answer:

B is the answer for this question. :)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Another day for brainliests if u answer my questions right :D

Mumz [18]

Because they will give you the same answers lol

6 0

3 years ago

Read 2 more answers

How many 4-digit numbers can be created from the digits 6, 4, 2, 9, 7 and 1 without repeating any?

Genrish500 [490]

Total sets of 4-digits = 6
Total 4-digit numbers formed by one set of number = 4
So, total numbers that can be formed = 6 × 4 = 24

8 0

3 years ago