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Shkiper50 [21]
3 years ago
6

Help with #17 please

Mathematics
1 answer:
ohaa [14]3 years ago
8 0
2 evens is an positive
1 odd,1 even is a odd
2 odd is an ofd
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a 28 ft. ladder leaning against a vertical wall makes an angel of 80 degrees with the ground. How far from the base of the wall
worty [1.4K]

Answer:

The ladder is 4.86 foot from the base of the wall .

Step-by-step explanation:

Given as :

The length of the ladder = 28 ft

The ladder makes angle of 80° with the ground

Let The distance of the ladder from the foot of the wall = x ft

Now, From Triangle BAC

Cos angle = \dfrac{\textrm Base}{\textrm Hypotenuse}

I.e Cos 80° = \dfrac{\textrm BA}{\textrm AC}

Or, 0.1736 =  \dfrac{\textrm x}{\textrm 28}

Or, x = 0.1736 × 28

∴  x = 4.86 foot

So, The distance of ladder from wall base = x =  4.86 foot

Hence The ladder is 4.86 foot from the base of the wall . Answer

3 0
3 years ago
How do you solve this system: y= -3/2x, and 3x+2y=-4 by substitution?
Soloha48 [4]
Download Photomath it will answer it with step by step work
4 0
3 years ago
Read 2 more answers
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{236100}{8} = 29512.5

Sum of squares of differences = 3408750

S.D = \sqrt{\frac{3408750}{7}} = 697.82

Population mean, μ = $30,000

Sample mean, \bar{x} = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars} We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975

Now,

t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894

Since,                  

t_{stat} < t_{critical}

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0
3 years ago
If s pool holds 22,000 gallon how long will it take to fill a pool at a rate of 400 gallon per minute round to the nearest tenth
worty [1.4K]
T=volume÷rate
this will cancel out gal and leave min

22000 gal ÷ 400 gal/min

55 min
3 0
3 years ago
Which is an asymptote of the graph of the function y = cot ( x - 2pi / 3 )
Sloan [31]
The answer to the equation is b
8 0
3 years ago
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