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butalik [34]
1 year ago
10

Complete the set of ordered pairs for the relation.

Mathematics
1 answer:
neonofarm [45]1 year ago
6 0

The set of ordered pairs is:

{(-2, 2), (-1, 0), (0, 2), (1, 4), (2, 6)}

<h3>How to complete the set of ordered pairs?</h3>

Here we have the relation:

y = 2*|x + 1|

And the domain is x ∈ { -2, -1, 0, 1, 2}

Evaluating in the values of the domain, we get:

if x = -2.

y = 2*|-2 + 1| = 2

Then we have the ordered pair (-2, 2)

if x = -1

y = 2*|-1 + 1| = 0

Then we have the ordered pair (-1, 0)

if x = 0

y = 2*|0 + 1| = 2

Then we have the ordered pair (0, 2)

if x = 1

y = 2*|1 + 1| = 4

Then we have the ordered pair (1, 4)

if x = 2

y = 2*|2 + 1| = 6

Then we have the ordered pair (2, 6)

The set of ordered pairs is:

{(-2, 2), (-1, 0), (0, 2), (1, 4), (2, 6)}

If you want to learn more about ordered pairs:

brainly.com/question/1528681

#SPJ1

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Natasha_Volkova [10]

this is the best thing i could find for you, good luck with your question,

5x is greater than or equal to -25

The product of 5 and a number is at least –25

we convert the given statement into inequality

product means multiplication

Let x be the unknown number

product of 5 and a number is 5x

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For word at most we use <=

for word at least we use >=

So the expression becomes 5x <= -25

6 0
3 years ago
What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2 + 3x^2y^2 + 3x^4y?
WINSTONCH [101]

Given:

The polynomials are:

3x^2y^2-2xy^5

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Solution:

We have,

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

The sum of given polynomials is:

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Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

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Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

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The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
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damaskus [11]
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This is 28 percent of the original price x

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