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2 years ago

Is the expression (5x5)^3 equivalent to 5x5^3

Mathematics

2 answers:

german2 years ago

6 0

Answer:

No.

Step-by-step explanation:

The order of operations in both problems are different, giving two very different results. Therefore, they are unequal.

Vadim26 [7]2 years ago

4 0

Answer: No it’s not……

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How do i answer other questions

vivado [14]

Just click on brainly the logo at the top left and then you will see questions there :)

8 0

3 years ago

Read 2 more answers

If a certain machine makes electrical resistors having a mean resistance of 40 ohms and a standard deviation of 2 ohms, what is

V125BC [204]

Answer:

The probability is $P(\= X < 40.4) = 0.84134$

Step-by-step explanation:

From the question we are told that

The mean is $\mu =40 \ \Omega$

The standard deviation is $\sigma = 2 \ \Omega$

The sample size is n = 25

The combined resistance is $\sum x_i = 1010 \ \Omega$

Generally the sample mean is mathematically represented as

$\= x = \frac{\sum x_i }{n}$

=> $\= x = \frac{1010 }{25}$

=> $\= x = 40.4 \ \Omega$

Generally the standard error of the mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{ 2 }{\sqrt{25} }$

=> $\sigma_{x} = 0.4$

Generally the probability that a random sample of 25 of these resistors will have a combined resistance of less than 1010 ohms is mathematically represented as

$P(\= X < 40.4) = P( \frac{\= X - \mu }{\sigma_{x }} < \frac{ 40.4 - 40 }{0.4} )$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

$P(\= X < 40.4) = P( Z < 1 )$

From the z table the area under the normal curve to the left corresponding to 1 is

$P(\= X < 40.4) = P( Z < 1 ) = 0.84134$

$P(\= X < 40.4) = 0.84134$

3 0

3 years ago

A real-estate company appraised the market value of 36 homes in Lyttelton and found that the sample mean and standard deviation

pantera1 [17]

Solution :

Sample size Sample mean Sample S.D.

Sample 1 $n_1=36$ $\bar{x}_1=150,000$ $s_1=17,000$

Sample 2 $n_2=45$ $\bar{x}_2=100,000$ $s_2=12,000$

$df = \frac{\left(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}\right)^2}{\frac{1}{n_1-1}\left(\frac{s_1^2}{n_1}\right)^2+\frac{1}{n_2-1}\left(\frac{s_2^2}{n_2}\right)^2}$

= 60

Therefore, significance level, α = 0.1

Critical value, t* = 1.6706

So, the margin of error, $t^*=\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

= 559.9896

Lower limit, $(\bar x_1-\bar x_2)-\text{(margin of error)}=44402.0104$

Upper limit, $(\bar x_1-\bar x_2)+\text{(margin of error)}=55597.9896$

Therefore 90% C.I. is (44402.0104, 55597.9896) or $44402.0104 < \mu_1 - \mu_2 < 55597.9896$

5 0

3 years ago

Help me, please!!!!! CORRECT ANSWER GETS BRAINLIEST!!!!!!

sladkih [1.3K]

Hello,

Here is your answer:

The proper answer to your question is..... 200,000=4x-20

When your doing questions like these make sure you pay attention to the question.

Your answer is 200,000=4x-20

If you need anymore help feel free to ask me!

Hope this helps!

5 0

3 years ago

Use the associative property to identify which expression is equal to (10)(5x)(7). 1.(7)(5x)(10) 2. 10(5x + 7) 3. (5x)(10)(7) 4.

8090 [49]

Associative property is dealing with parentahsees and orders
it is
a(bc)=(ab)c and
a+(b+c)=(a+b)+c

so we want the multiplication one

given
(10)(5x)(7)
we can arragnge these a number of ways (we should use commutative property, but whatever)

first one works, the 7 was moved to front
2nd is wrong, that is a wierd version of the distributive
3rd is right, 5x was moved to the front
4th is wack, no bueno

answer is 1st and 3rd options

6 0

3 years ago