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2 years ago

The lengths of two sides of an isosceles triangle are eight and 10. what is the length of the third side

1 answer:

3 0

The length of the third side can be either 10 or 8, if the lengths of two sides of an isosceles triangle are eight and 10.

According to the given question.

The lengths of two sides of an isosceles triangle are 8 and 10.

Since, the properties of an isosceles triangle are

Two sides are congruent to each other.
The sum of the length of the two sides of a triangle is greater than the length of the third side.
The difference between the two sides of a triangle is less than the length of the third side.

So, according to the property of an isosceles triangle

The third side must be less than the sum of 8 and 10.

⇒ length of third side < 8 + 10

⇒ length of third side < 18

And,

Length of the third side > 10 - 8

⇒ length of the third side > 2

But, the triangle is an isosceles triangle therefore, the third side must be either 8 or 10.

And

8 or 10 both are less than 18 and greater than 2.

Therefore, the length of the third side can be either 10 or 8.

Find out more information about isosceles triangle here:

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What relationship exists between a homogeneous mixture and the number of phases in the mixture

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The relationship that exists between a homogeneous mixture and the number of phases in the mixture is one phase.

Given that there is a relationship exists between a homogeneous mixture and the number of phases in the mixture.

We are required to tell the name of the relationship that exists between a homogenous mixture and the number of phases in the mixture.

A homogeneous mixture is basically a gaseous, liquid or solid mixture that has the same proportions of its components throughout a given sample.

The name of the relationship is one phase.

A phase is basically a relationship between the cycles of different periodic waves.

Hence the relationship that exists between a homogeneous mixture and the number of phases in the mixture is one phase.

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2 years ago

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3 years ago

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At an ocean depth of 20 meters, a buoy bobs up and then down 2 meters from the ocean's depth. Four seconds pass from the time th

stiv31 [10]

The first and second coordinate points of the sine graph are;

(0, 20) and (2, 22)

<h3>Sine Graph expression</h3>

The general formula we will use to plot the graph is;

y = [Asin (2πx/t)] + ∅ (Note that sin is in radians)

where;

A is amplitude

t is period

∅ is phase shift

We are told that the buoy bobs up and then down 2 meters from the ocean's depth. This means that;

Amplitude; A = 2

Now, Four seconds pass from the time the buoy is at its highest point to when it is at its lowest point. Thus;

Period = 2 * 4 = 8 seconds

Assume at x = 0, the buoy is at normal ocean depth. Thus;

Phase shift; ∅ = 20

Thus, we have;

y = [2sin((2πx/8)] + 20

At x = 0, we have;

y = [2sin((2π*0/8)] + 20

y = 0 + 20

y = 20

Thus, first point is; (0, 20)

Since the second point must be a maximum or minimum value on the graph closest to the first point, then we put 2 for x to get the coordinate of the second point;

y = [2sin((2π*2/8)] + 20

y = [2sin(π/2)] + 20

In radians, sin(π/2) = 1. Thus;

y = (2 * 1) + 20

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Using the first and second point coordinates, we will use sine tool to graph the function as attached below.

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3 years ago

What is the best way to arrange the magnets on the train and on the track so that the model train levitates? flat, so that the n

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The best way is: B. flat, so that the north pole of the magnets on the train point up and the north poles of the magnets on the track point down.

<h3>What is the law of magnetism?</h3>

The law of magnetism states that the like poles of a magnet repel one another while unlike (different) poles attract each other. Thus, two north (N) poles of a magnet would repel one another while a north (N) and south (S) would attract each other.

Based on the law of magnetism, the best way to arrange the magnets on the train and on the track, so as to allow the model train levitate is flat, as this would make the north (N) pole of the magnets on the train point up and the north (N) poles of the magnets on the track point down.

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<u>Complete Question:</u>

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What is the best way to arrange the magnets on the train and on the track so that the model train levitates?

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