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2 years ago

Explain how neonicotinoid use relates to larger environmental principles

2 answers:

6 0

The use of neonicotinoids affect the environment because they are pollinators and they also negatively influence aquatic ecosystems, especially those of nontarget form of aquatic invertebrate communities.

<h3>What is the effect of a neonicotinoid pesticide?</h3>

The use of neonicotinoids is one that affect the environment as it is known to act as pollinators that affects nontarget aquatic invertebrate communities. The neonicotinoid toxicity is known to be very toxic toward any form of aquatic arthropods .

Neonicotinoids are said to be a widely-used form of pesticides that is said to have sub-lethal effects on bees' foraging and also in regards to colony performance.

Hence, The use of neonicotinoids affect the environment because they are pollinators and they also negatively influence aquatic ecosystems, especially those of nontarget form of aquatic invertebrate communities.

Learn more about neonicotinoids from

brainly.com/question/27626853

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Lana71 [14]2 years ago

6 0

Answer: toe eater

Explanation:

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posledela

The answer is most likely (c.) the spinal cord

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3 years ago

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1. Ito'y nabubuo kung pagsasamahin ang mga guhit latitude at guhit longitude sa mapa ng mundo o globo. A. Prime Meridian B. Digr

marishachu [46]

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c.International Dateline

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3 years ago

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makkiz [27]

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3 years ago

This assignment is due is half an hour and I'm really lost

Zolol [24]

Answer:

$3B - 4C = \left[\begin{array}{cc}-8 &-23\\1&-15\end{array}\right]$

Explanation:

Given

$B = \left[\begin{array}{cc}8&-5\\-1&3\end{array}\right]$

$C = \left[\begin{array}{cc}8&2\\-1&6\end{array}\right]$

Required

Determine 3B - 4C

$B = \left[\begin{array}{cc}8&-5\\-1&3\end{array}\right]$

Then

$3B = 3 * \left[\begin{array}{cc}8&-5\\-1&3\end{array}\right]$

$3B = \left[\begin{array}{cc}24&-15\\-3&9\end{array}\right]$

Similarly,

$C = \left[\begin{array}{cc}8&2\\-1&6\end{array}\right]$

Then

$4C = 4 * \left[\begin{array}{cc}8&2\\-1&6\end{array}\right]$

$4C = \left[\begin{array}{cc}32&8\\-4&24\end{array}\right]$

So:

$3B - 4C = \left[\begin{array}{cc}24&-15\\-3&9\end{array}\right] - \left[\begin{array}{cc}32&8\\-4&24\end{array}\right]$

This gives:

$3B - 4C = \left[\begin{array}{cc}24 - 32 &-15-8\\-3-(-4)&9-24\end{array}\right]$

$3B - 4C = \left[\begin{array}{cc}-8 &-23\\1&-15\end{array}\right]$

5 0

3 years ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0

2 years ago