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mixas84 [53]
2 years ago
10

Small tug boats pull cruise ships up and down rivers to prevent them from grounding. Cruise ships anchor 22 km away from the riv

er port. A tug boat can travel 20 km downstream in the same time it takes it to travel 10 km upstream. If the speed of the current is 5 km/h, calculate the time it takes for the tug boats to travel upstream from the cruise ship to the river port.
Mathematics
1 answer:
Shalnov [3]2 years ago
6 0

Answer:

2.2 hr

Step-by-step explanation:

Let the speed of the boat in km/h be x.

Then, the speed downstream is (x+5), and the speed upstream is (x-5).

We know the speed downstream is twice the speed upstream, so

x+5=2(x-5) \\ \\ x+5=2x-10 \\ \\ x=15

This means the speed upstream is 10 km/h. Thus, to travel 22 km, it will take 2.2 hrs.

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Subtract 0000 1000 whats the answer
Finger [1]
If u subtract 1,000 - 0000 it will equal 1,000

8 0
4 years ago
Which of the follwing is true 3 3/9+7 6/11=10 87/99 2 3/8+6 4/5=8 12/40 ,3 3/7+4 2/3=7 2/21 4 5/6+5 5/7=9 10/13
garri49 [273]

Answer: 3 3/9+7 6/11 = 10 87/99

Step-by-step explanation:

a. 3 3/9+7 6/11 = 10 87/99

First and foremost, we need to know the lowest common multiple of 9 and 11 which is 99.

Therefore, 3 3/9 + 7 6/11 would be:

= 3 33/99 + 7 54/99

= 10 87/99

This is correct

b. 2 3/8 + 6 4/5 = 8 12/40

First and foremost, we need to know the lowest common multiple of 8 and 5 which is 40.

Therefore, 2 3/8 + 6 4/5 would be:

= 2 15/40 + 6 32/40

= 8 47/40

= 9 7/40

Since the answer gotten is 8 12/40. This is wrong.

c. 3 3/7 + 4 2/3 = 7 2/21

First and foremost, we need to know the lowest common multiple of 7 and 3 which is 21.

Therefore, 3 3/7 + 4 2/3 would be:

= 3 9/21 + 4 14/21

= 7 23/21

= 8 2/21

Since the answer gotten is 7 2/21. This is wrong.

d. 4 5/6 + 5 5/7 = 9 10/13

First and foremost, we need to know the lowest common multiple of 6 and 7 which is 42.

Therefore, 4 5/6 + 5 5/7 would be:

= 4 35/42 + 5 30/42

= 9 65/42

= 10 23/42

This is wrong as the answer gotten is 9 10/13

Therefore, the true option is

3 3/9+7 6/11 = 10 87/99

7 0
3 years ago
Please help i’ll do anything and give the brain thing :((
ASHA 777 [7]

Answer:

add me on snap kharding1805 and I will add you back

3 0
3 years ago
This problem really confuses me, help?
OLga [1]
So k in the first problem would =1/2
and i guess in the second problem just put k in place of the first space and in the second space put 8 for x. y would then =4. Idk if I did this right, though, I'm honestly a little confused too.
3 0
4 years ago
Read 2 more answers
The answer for (a) is 28 and the answer for (b) is 13 but I don’t know how to get the answer
denis-greek [22]

Answer:

Step-by-step explanation:

If Quan had 15 and Kaden had 3 times as much, then Kaden had 15(3) = 45. If he spent 10 then he had 35 left. The amount of money Quan had after his mom gave him some was 4/5 the amount of Kaden's 35 (let x = the amount of money Quan has after his mom gives him some):

x=\frac{4}{5}(35)  35 divides by the 5 in the denominator 7 times, and 7 times 4 is 28. That's how you get your 28 in part a.

For part b., he started with 15 and ended with 28, so his mom gave him 28-15=13. That's how you get the 13.

8 0
3 years ago
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