Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.
<u>Step-by-step explanation:</u>
As given by the statement in the problem,
Q may be the middle point, which cut the diagonal PA into 2 equal halves.
In rhombus, diagonals meet at right angles.
which means that PQ = QA
x+2 = 3x - 14
Grouping the terms, we will get,
3x -x = 14+ 2
2x = 16
dividing by 2 on both sides, we will get,
x = 16/2 = 8
8+2 = 3(8) - 14 = 10 = PQ or QA
Answer:
b = a + 3.75
Step-by-step explanation:
a = 4b - 15
You are solving for b. Isolate the b. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, add 15 to both sides
a (+15) = 4b - 15 (+15)
a + 15 = 4b
Next, divide 4 from both sides. Remember to divide from all terms.
(4a + 15)/4 = (4b)/4
b = (4a)/4 + (15)/4
b = a + 15/4
b = a + 3.75 is your answer
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The least to greatest would be 2/6, 3/6, 5/6.
As they all have the same denominator you look at the numerator to figure out the least to greatest. 2/6 is the shortest yard and 5/6 is the longest yard so it would be greater than 2/6.
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the number of free throws = x
And the number of regular field goals = y
Total shots made by the team = 31
Equation for the shots will be,
x + y = 31 ------(1)
If the team gets 1 point for free throws and 2 points for a regular field goal,
x + 2y = 49 --------(2)
[total points gained by the team = 49]
1). Option (2) is the correct option.
2). Subtracting equation (1) from equation (2),
(x + 2y) - (x + y) = 49 - 31
y = 18
Therefore, number of regular field goals made by the team = 18
