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2 years ago

If one class in such a distribution is 80-89, the lower class limit is enter your response here and the upper class limit is?

1 answer:

5 0

If the data presentation in Exercise 2 is varied by organizing the data into classes, the data presentation is called a grouped frequency distribution . If one class in such a distribution is 80-89, the lower class limit is 80 and the upper class limit is 89.

What is the formula for grouped frequency distribution?

A grouped frequency distribution shows the scores by grouping the observations into intervals and then lists these intervals in the frequency distribution table.
The intervals in grouped frequency distribution are called class limits.

What is the formula for grouped frequency distribution?

In other words, the mean for a population can be found by dividing ∑ m f by , where is the midpoint of the class and is the frequency.
As a result, the formula μ = ∑ m f N can be written to summarize the steps used to determine the value of the mean for a set of grouped data.

Learn more about grouped frequency distribution

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The complete question is -

If the data presentation in Exercise 2 is varied by organizing the data into classes, the data presentation is called a ______________. If one class in such a distribution is 80-89, the lower class limit is 80 and the upper class limit is 89.

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When the area in square units of an expanding circle is increasing twice as fast as its radius in linear units, the radius is...

enot [183]

Answer:

c. $\frac{1}{\pi}$

Step-by-step explanation:

We have been given that the area in square units of an expanding circle is increasing twice as fast as its radius in linear units

We will use derivatives to solve our given problem.

We know that area (A) of a circle is equal to $A=\pi r^2$ .

Let us find derivative of area function with respect to time.

$\frac{dA}{dt}=\frac{d}{dt}(\pi r^2)$

Bring out constant:

$\frac{dA}{dt}=\pi \frac{d}{dt}(r^2)$

Using power rule and chain rule, we will get:

$\frac{dA}{dt}=\pi(2r)* \frac{dr}{dt}$

$\frac{dA}{dt}=2\pi r*\frac{dr}{dt}$ Here $\frac{dr}{dt}$ represents change is radius with respect to time.

We have been given that area of an expanding circle is increasing twice as fast as its radius in linear units. We can represent this information in an equation as:

$\frac{dA}{dt}=2\frac{dr}{dt}$

$2\pi r* \frac{dr}{dt}=2\frac{dr}{dt}$

$2\pi r=2$

$\frac{2\pi r}{2\pi}=\frac{2}{2\pi}$

$r=\frac{1}{\pi}$

Therefore, the radius is $\frac{1}{\pi}$ and option 'c' is the correct choice.

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3 years ago

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kirza4 [7]

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3 years ago

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frutty [35]

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3 years ago

Please answer if you know the answer

Fofino [41]

Answer:

2:5, 5:2

Step-by-step explanation:

Lets use 30 and 12. 12 divided by 30 is 0.4, which reduced is 2:5, or u can write 0.4. Thats oil to flour

But opposite numbers for flour to oil, bc of common sense.

Hope this helps(would be appreciated if you mark this answer brainliest bc need for lvl up. )

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3 years ago

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xenn [34]

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3 years ago

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